Answer: 2 - 2*sin³(θ) - √1 -sin²(θ)
Step-by-step explanation: In the expression
cos(theta)*sin2(theta) − cos(theta)
sin (2θ) = 2 sin(θ)*cos(θ) ⇒ cos(θ)*2sin(θ)cos(θ) - cos(θ)
2cos²(θ)sin(θ) - cos(θ) if we use cos²(θ) = 1-sin²(θ)
2 [ (1 - sin²(θ))*sin(θ)] - cos(θ)
2 - 2sin²(θ)sin(θ) - cos(θ) ⇒ 2-2sin³(θ)-cos(θ) ; cos(θ) = √1 -sin²(θ)
2 - 2*sin³(θ) - √1 -sin²(θ)
Answer:
7
x
−
5 y = − 110
Step-by-step explanation:
Step-by-step explanation:
![\cos 90 \cos 30 + \sec^2 45 \sin 30 - \cos 270 \sin 180](https://tex.z-dn.net/?f=%5Ccos%2090%20%5Ccos%2030%20%2B%20%5Csec%5E2%2045%20%5Csin%2030%20-%20%5Ccos%20270%20%5Csin%20180)
But we know that
![\cos 90 = \cos 270 = \sin 180 = 0](https://tex.z-dn.net/?f=%5Ccos%2090%20%3D%20%5Ccos%20270%20%3D%20%5Csin%20180%20%3D%200)
and
![\sin 30 = \dfrac{\sqrt{3}}{2} \:\:\text{and}\:\: \sec 45 = \sqrt{2}](https://tex.z-dn.net/?f=%5Csin%2030%20%3D%20%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%20%5C%3A%5C%3A%5Ctext%7Band%7D%5C%3A%5C%3A%20%5Csec%2045%20%3D%20%5Csqrt%7B2%7D)
so this leaves us with just
![\sec^2 45 \sin 30 = (\sqrt{2})^2 \left(\dfrac{\sqrt{3}}{2} \right)= \sqrt{3}](https://tex.z-dn.net/?f=%5Csec%5E2%2045%20%5Csin%2030%20%3D%20%28%5Csqrt%7B2%7D%29%5E2%20%20%5Cleft%28%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%20%5Cright%29%3D%20%5Csqrt%7B3%7D)
Answer:
C. 56
Step-by-step explanation:
7*8=56
Juan rode the slowest. It took him 5 minutes to go 2 blocks and another 3 minutes to go 2 more blocks. It was taking him longer minutes to go 2 blocks at a time. Took Juan 17 minutes to do 8 blocks and Rita did 8 blocks in 8 minutes she was faster. Hope this helps