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alexandr1967 [171]
3 years ago
8

The fourth grade student at Riverside school are going on a field trip . There are 68 student on each of the four buses. How man

y students are going on the field trip?
Mathematics
2 answers:
Snezhnost [94]3 years ago
5 0
Imagine 4 buses, if each bus has 68 students than that's the same adding 68+68+68+68 or 68x4
earnstyle [38]3 years ago
3 0
This answer is 272 I know because I did it vertically
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Find the solution to the differential equation dx/dy+y/3=0 subject to the initial conditions y(0)=12.
ycow [4]
\dfrac{\mathrm dx}{\mathrm dy}+\dfrac y3=0\iff\mathrm dx=-\dfrac y3\,\mathrm dy
\implies\displaystyle\int\mathrm dx=-\frac13\int\mathrm y\,dy
\implies x=-\dfrac16y^2+C

Given that y(0)=12, we have

0=-\dfrac16(12)^2+C\implies C=24

So the particular solution to the initial value problem is

x=-\dfrac16y^2+24\iff y^2=144-6x
8 0
3 years ago
4(x-5) +2 =x+3 <br><br> I need help on this ! I don’t get it picture above !
algol [13]

Answer:

x=-5

Step-by-step explanation:

4(x-5)+2=x+3 As the first step says, distribute the 4 (multiply all numbers in the parentheses by 4).

4x-20+2=x-3 Combine like terms. For example, the -20 and 2 are like terms because they are both their own numbers and not attached to a variable.

4x-18=x-3       Subtract x from each side. Now, we can get x to only one side.

<u>-x       -x</u>

3x-18=-3         Add 18 to both sides.

  <u>+18 +18</u>

3x=-15            Divide both sides by 3.

<u>/3   /3</u>

x=-5

I hope this helped you!! Have a great day c:

6 0
3 years ago
Show how to solve the problem 378×6 Using Pl. value with regrouping explain how you knew when to regroup
Fynjy0 [20]
378
x  6        
six is your base number.. then you do 6x8 which is 48 you will leave the 8 under the ones column and carry the 4 above the seven then you do 7x6 plus the 4.   

I think that's how i learned it
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5 0
3 years ago
Write a two point slope equations for the line passing through the points 6,5 and 3,1
Gwar [14]

The 2-point form of the equation of a line can be written as ...

... y = (y2-y1)/(x2-x1)·(x -x1) +y1

For your points, this is ...

... y = (1-5)/(3-6)·(x -6) +5

... y = (4/3)(x -6) +5

It can also be written as

... y -5 = (4/3)(x -6)

3 0
3 years ago
Read 2 more answers
Write an equation of a circle that has the center at the origin and goes through (-3,-6)
dexar [7]

Answer:

x^{2} +y^{2} = 45

Step-by-step explanation:

General Equation of circle is

(x-x_1)^{2} +(y-y_1)^{2} = r^{2}----------- (1)

Here

(x_1, y_1)= (0, 0)

Radius r is distance from origin (x1, y1) to point (x2, y2)=(-3, -6)

r=\sqrt{(x_2-x_1)^{2} + (y_2-y_1)^{2} }

r= \sqrt{(-3-0)^{2} + (-6-0)^{2} }

r= \sqrt{9+36}

r=\sqrt{45}

Substituting values in equation (1)

(x-0)^{2} +(y-0)^{2} =( \sqrt{45})^{2}

x^{2} +y^{2} = 45

6 0
3 years ago
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