Answer:
12 ft 9 5/6 inches
Step-by-step explanation:
We can use proportions to solve this. Put the height of the object over the shadow. Change the height of the object to inches
Alonzo
5 ft 11 inches = 5 ft *12 inches/ft + 11 inches = 60 inches + 11 inches = 71 inches
2 ft shadow = 2* 12 inches/ ft = 24 inches
Basketball goal
4 ft 4 inches = 4 ft *12 inches/ft + 4 inches = 48inches + 4 inches = 52 inches
Alonzo Basketball
71 inches x inches tall
------------ = --------------------
24 inches 52 inches
Using cross products
71*52 = 24*x
Divide each side by 24
71*52/24 = 24x/24
923/6 =x
Lets change this to a mixed number
6 goes into 923 153 times with 5 left over
153 5/6 inches
Now we need to change inches to feet
How many time does 12 go into 153 12 times (12*12 =144 with 9 left over)
12 ft 9 5/6 inches
Answer:
there is a 20% probability that the chosen student plays neither
Step-by-step explanation:
14+2+2=16
20-16=4
4/20= 1/5
1/5= 0.2
0.2= 20%
Step-by-step explanation:
d(t) = -16t² + 96t + 112
A) The quarter's initial height is at t = 0.
d(0) = -16(0)² + 96(0) + 112
d(0) = 112
The quarter is tossed from a height of 112 feet.
B) The maximum height is at the vertex of the parabola, which is at x = -b/(2a).
t = -(96) / (2 × -16)
t = 3
The quarter reaches its maximum height after 3 seconds.
C) d(3) = -16(3)² + 96(3) + 112
d(3) = 256
The quarter reaches a maximum height of 256 feet.
D) When the quarter lands in the water, d(t) = 0.
0 = -16t² + 96t + 112
0 = t² − 6t − 7
0 = (t + 1) (t − 7)
t = -1 or 7
Since t can't be negative, t = 7. So the quarter lands in the water after 7 seconds.
Answer:
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Answer:
The probability is 
Step-by-step explanation:
If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:
If k=1
Because, in her first try she has n possibles options and just one give her a successful login.
If k=2
Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.
If k=3
Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.
Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n
