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andrew11 [14]
3 years ago
8

Determine the number and type of zeros of the quadratic function based on the value of the discriminant​

Mathematics
2 answers:
Katarina [22]3 years ago
6 0

Answer:

See below

Step-by-step explanation:

if b^2 - 4ac is greater than 0 then there are 2 answers that are not equal to each other, but both are real.

If b^2 - 4ac = 0 then you have two real answers that are equal

The real problem is what happens when b^2 - 4ac is less than 0? In this case the answer is a complex number of the form

a + bi

a - bi

where i is the square root of - 1

stellarik [79]3 years ago
3 0

Answer: see below all answers

Step-by-step explanation:

2 Real  Numbers Solutions: Answers

Discriminant =100

Discriminant = 2

Discriminant = 3

1 Real Number Solution: Answer

Discriminant =0

0 Real Number Solution: Answers

Discriminant = -4

Discriminant = -36

ed2020

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The equation a2 + b2 = ca represents the relationship between the three sides of a right triangle.
choli [55]

Answer:

Step-by-step explanation:

I think you mean a² + b² = c², not ca.

a = 10, c = 26

b² = c²  - a² = 26² - 10² = 576

b = √576 = 24 ft

3 0
3 years ago
Matthew accepted a new job at a company with a contract guaranteeing annual
guajiro [1.7K]

Answer:

S= 4000n+50000

Step-by-step explanation:                       Table

50000+4000=54000                         0           5000

54000+4000=58000                         1            54000

58000+4000=62000 etc..                2            58000

                                                            3           62000

Is increasing by 4000  and thats the rate of change so S=4000n

And the y intercept always will be with a 0 in the cordinates and the only with a 0 is 50000.

We put all together and it will be

Answer: S=4000n+50000

5 0
3 years ago
3.84761 to 3 decimal place
yKpoI14uk [10]
The answer is 3.848.
3 0
2 years ago
The sum of a rational number and an even integer is rational. A) Always True B) Sometimes True C) Usually True D) Never True
SOVA2 [1]
I think that the sum will always be a rational number
let's prove that


<span>any rational number can be represented as a/b where a and b are integers and b≠0

</span>and an integer is the counting numbers plus their negatives and 0
so like -4,-3,-2,-1,0,1,2,3,4....

<span>so, 2 rational numbers can be represented as

</span>a/b and c/d (where a,b,c,d are all integers and b≠0 and d≠0)

their sum is
a/b+c/d=
ad/bd+bc/bd=
(ad+bc)/bd

1. the numerator and denominator will be integers
2. that the denominator does not equal 0

alright
1.
we started with that they are all integers
ab+bc=?
if we multiply any 2 integers, we get an integer
<span>like 3*4=12 or -3*4=-12 or -3*-4=12, etc.
</span>even 0*4=0, that's an integer
the sum of any 2 integers is an integer
like 4+3=7, 3+(-4)=-1, 3+0=3, etc.
so we have established that the numerator is an integer

now the denominator
that is just a product of 2 integers so it is an integer


<span>2. we originally defined that b≠0 and d≠0 so we're good

</span>therefore, the sum of any 2 rational numbers will always be a rational number <span>is the correct answer.</span>
6 0
3 years ago
HELP ME I NEED SOMEONE TO SHOW WORK AND AWNSER QUESTION ITS TIMED PLEASE HURRY 30 POINTS FOR IT!
vodka [1.7K]

Answer:

Just like how we did the other one, you will do the same thing. Hope this helps, thank you !!

3 0
3 years ago
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