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kiruha [24]
3 years ago
10

I really need help it’s very hard

Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

The angle ZLK has a value of 75 degrees.

Step-by-step explanation:

We can calculate this as:

m\angle MLZ+m\angle ZLK=m\angle MLK\\\\(x+66)+(x+86)=130\\\\2x+152=130\\\\2x=130-152\\\\x=-22/2=-11\\\\\\m\angle ZLK=x+86=-11+86=75

We replace the angles values in the equation, as both angles that are formed with Z (MLZ and ZLK), when added, gives as the angle MLK. This allows us to calculate x. The value for x is -11.

Then, with the value for x we can calculate any of both angles.

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Erin gets her exercise by running. The graph shows the distances she covers in a given amount of time. How many hours does it ta
ivanzaharov [21]

Answer:

2½ h  

Step-by-step explanation:

Assume the graph is like the one below.

The graph shows how Erin's distance varies with time.

To find out how long it takes Erin to cover 25 mi, find 25 mi on the vertical axis.

From there, draw a horizontal line until it hits the graph.

Then drop a vertical line to the horizontal axis.

It hits half-way between 2 and 3.

It takes Erin 2½ h to run 25 mi.

7 0
3 years ago
Read 2 more answers
Choose the correct slope of the line that passes through the points (1, −3) and (3, −5).
Flura [38]
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(y2-y1)/(x2-x1)

we have
(1,-3) and (3,-5)
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x2=3
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4 0
3 years ago
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Find the following of each arc measure
Dimas [21]
ZW= 108
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8 0
3 years ago
A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil
erma4kov [3.2K]

Answer:

\frac{n_p}{n_s}=\frac{1}{1000}

Step-by-step explanation:

Given voltage of primary coil is V_p=12V

And voltage of secondary coil is V_s=12,000V

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil (n_p) and secondary coil (n_s).

Following equation represents the relation between them.

\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

\frac{n_p}{n_s}=\frac{1}{1000}

5 0
3 years ago
Pls help me solve this one please..<br> (3/4)to the 2nd power +(1/2)to the second power
andriy [413]
9/16 + 1/4
9+4/16
13/16

Alternative form
0.8125
5 0
3 years ago
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