t= 2.25 secs
Step-by-step explanation:
Step 1 :
Equation for motion with uniform acceleration is v = u+ at
where v is the final velocity
u is the initial velocity
a is the acceleration due to gravity
and t is the time
Step 2 :
Here , v = 0 because at the highest point final velocity is 0.
u = 72 feet/sec
a = -32 ft/sec^2
We need to find the time t.
Substituting in the equation we have,
0 = 72 -32 * t
=> 32 t = 72
=> t = 72/32 = 2.25 secs
Step-by-step explanation:
It is shifted down 2 units.
Answer:
D. x = 10, m<TRS = 60°
Step-by-step explanation:
m<QRS = 122° (given)
m<QRT = (7x - 8)° (given)
m<TRS = (6x)° (given)
m<QRT + m<TRS = m<QRS (angle addition postulate)
(7x - 8)° + (6x)° = 122° (substitution)
Solve for x
7x - 8 + 6x = 122
Add like terms
13x - 8 = 122
13x = 122 + 8
13x = 130
x = 130/13
x = 10
✔️m<TRS = (6x)°
Plug in the value of x
m<TRS = (6*10)° = 60°