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Dovator [93]
3 years ago
5

What is a three digit number thats an odd multiple of three and the product of its digits is 24 and is larger than 15 squared?

Mathematics
1 answer:
Reika [66]3 years ago
7 0
The only way 3 digits can have product 24 is 
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4 
To be divisible by 3 the sum of the digits must be divisible by 3.
1+  3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3. 

So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.

Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.

The others must end in 3. 

They must be greater than 152 which is 225. So the

First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.

The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.  
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
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Rama is stringing beads whose lengths are each 0.19 inches. How can rounding be used to estimate the length of a row of 9 beads?
Mice21 [21]

Since the beads are about 0.20 inches, the length of a row of 9 beads will be approximately 9 × 0.20 = 1.80 inches.

Step-by-step explanation:

According to given statement;

Length of individual stringing beads = 0.19 inches

Rounding off = 0.2 inches

Length of row of 9 beads = 9* rounded off length of individual beads

Length of row of 9 beads = 9*0.2

Length of row of 9 beads = 1.80 inches

Since the beads are about 0.20 inches, the length of a row of 9 beads will be approximately 9 × 0.20 = 1.80 inches.

Keywords: multiplication

Learn more about multiplication at:

  • brainly.com/question/4767370
  • brainly.com/question/4770453

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At 3pm, the length of the shadow of a thin vertical pole standing on level ground is the same as the height of the pole. A while
aliya0001 [1]

Answer: The height of the pole is 175.97 ( approx )

Step-by-step explanation:

Let the height of the pole is x cm,

Also, let the angle of elevation of the sun to the pole at 3 pm is \theta

Thus, by the question,

tan\theta = \frac{\text{ The height of the pole}}{\text{ The height of the shadow}}

\implies tan\theta = \frac{x}{x}    ( at 3pm the height of shadow = height of the pole)

\implies tan\theta = 1

\implies \theta = 45^{\circ}

Again, according to the question,

When the angle of elevation is   (\theta - 12^{\circ}),

The height of shadow = x + 95,

\implies tan(45-12)^{\circ}=\frac{x}{x+95}

\implies tan 33^{\circ}=\frac{x}{x+95}

\implies tan 33^{\circ}x + 95\times tan33^{\circ}=x

\implies tan 33^{\circ}x - x = - 95\times tan33^{\circ}

\implies -0.3505924068 x = - 61.6937213538

x=175.969930202\approx 175.97\text{ cm}

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3 years ago
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