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ss7ja [257]
2 years ago
9

What's the slope equation to points 1, 8 and 0, 5

Mathematics
1 answer:
Firdavs [7]2 years ago
7 0

Answer:

m= \frac{5-8}{0-1}

-3/-1

Step-by-step explanation:

You might be interested in
A candidate scored 32 marks out of 80,
Verizon [17]

Answer:

40%

Step-by-step explanation:

you need to divide 80 by 8 to get 10 and then divide 32 by 8 aswell. this gives you 4/10 which is equivalent to 40/100 or 40%

6 0
3 years ago
Avery has saved $295 to spend on Christmas gifts for 11 people. Which is the BEST estimate of the amount he can spend for each p
Juliette [100K]

Answer:

The best estimate is 27 dollars.

Step-by-step explanation:

When you divide 295 dollars by 11, you will get a very long decimal, do the first 2 numbers of the 1s place and 10s place in the decimal. After that, you have to round the 26.81. Since 8 is bigger than 5, you can round it to 27.00, and get your answer, which is 27 dollars.

8 0
3 years ago
Find the gcf of 12,30,72
kvv77 [185]

Answer: 6


Step-by-step explanation:

12 = 2^2 • 3

30 = 2 • 3 • 5

72 = 2^3 • 3^2


7 0
2 years ago
Martha is following a recipe for 13 liters of punch that uses 8 liters
trasher [3.6K]

Answer:

For every 1 liter of lemonade Martha has to add 1.6 liters of pineapple juice.

The ratio of liters of pineapple juice to liters of punch is 8:13

Step-by-step explanation:

13 - 8 = 5

5 divided by 5 is 1

8 divided by 5 is 1.6

8 0
2 years ago
Derive these identities using the addition or subtraction formulas for sine or cosine: sinacosb=(sin(a+b)+sin(a-b))/2
Sergeu [11.5K]

Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b).

The sine difference identity is:

\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a).

The cosine addition identity is:

\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b).

The cosine difference identity is:

\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b).

We need to find a way to put some or all of these together to get:

\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}.

So I do notice on the right hand side the \sin(a+b) and the \sin(a-b).

Let's start there then.

There is a plus sign in between them so let's add those together:

\sin(a+b)+\sin(a-b)

=[\sin(a+b)]+[\sin(a-b)]

=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]

There are two pairs of like terms. I will gather them together so you can see it more clearly:

=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]

=2\sin(a)\cos(b)+0

=2\sin(a)\cos(b)

So this implies:

\sin(a+b)+\sin(a-b)=2\sin(a)\cos(b)

Divide both sides by 2:

\frac{\sin(a+b)+\sin(a-b)}{2}=\sin(a)\cos(b)

By the symmetric property we can write:

\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}

3 0
3 years ago
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