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Kitty [74]
2 years ago
5

Find the circumference of the pizza to the nearest hundredth.

Mathematics
1 answer:
Ludmilka [50]2 years ago
8 0

Complete Question

Find the circumference of the pizza to the nearest hundredth.

When Diameter = 18 in.

Answer:

56.55 inches

Step-by-step explanation:

A pizza is circular in shape.

The formula for the circumference of a circle is given as:

πD

Where D = Diameter

From the above question,

Diameter = 18 inches

Hence,

Circumference of the circular pizza = π × 18 inches

= 56.548667765 inches

Approximately = 56.55 inches

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Hitman42 [59]

Answer:

a) C(x) is increasing in two regions: (i) (+\infty, 8\,s) and (ii) (10\,s,+\infty).

b) C(x) decreases in (8\,s, 10\,s).

Step-by-step explanation:

Let C(x) = x^{3}-27\cdot x^{2}+240\cdot x +850, where x is the quantity of insecticide, measured in hundreds of liters, and C(x) is the total manufacturing cost as a function of the quantity of the insecticide, measured in US dollars. A possible approach to determine which regions of C(x) are decreasing and increasing by means of the first derivative and graphing tools. The first derivative of the function is:

C'(x) = 3\cdot x^{2}-54\cdot x+240 (1)

Please notice that regions where C(x) is increasing has C'(x) > 0, whereas C'(x) < 0 when C(x) < 0.

We notice that C(x) is increasing in two regions: (i) (+\infty, 8\,s) and (ii) (10\,s,+\infty). Besides, C(x) decreases in (8\,s, 10\,s).

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3 years ago
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Papessa [141]

Answer:

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True or False (&amp; Justify): If a ball is thrown horizontally from the top edge of a 150m building at a speed of 25 m/sec, the
kap26 [50]

Answer:

38.6 m/s

Step-by-step explanation:

The motion of the ball is a projectile motion, which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

Therefore we have to analyze the horizontal and vertical motion separately.

Along the horizontal direction, the velocity is constant during the motion, since there are no forces acting in this direction. So the horizontal velocity 3 seconds after the launch will be the same as the velocity at the launch:

v_x = v_0 = 25 m/s

The vertical velocity instead changes according to the suvat equation:

v_y = u_y - gt

where

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g=9.8 m/s^2 is the acceleration due to gravity

t is the time

Therefore, after t = 3 s,

v_y=0-(9.8)(3)=-29.4 m/s

So the velocity after 3 seconds is < 25, -29.4 > m/s. The magnitude of the velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{25^2+(-29.4)^2}=38.6 m/s

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Give me any equation in the comments
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110*(3*3)

Step-by-step explanation:

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