Answer:
1 gamma = 15/8 alphas
Step-by-step explanation:
so we start by finding out what 1 gamma and 1 beta equals.
we know 4 gammas = 5 betas so if we divide by four on both sides we get:
1 gamma = 5/4 betas. we can apply that same procedure to 2 betas = 3 alphas and get 1 beta = 3/2 alphas
we know that 1 gamma = 5/4 betas and 1 beta = 3/2 alphas so how many alphas = 5/4 betas? using a proportion of ((3/2)/1) = ((x)/(5/4)) we can find that 5/4 betas = 15/8 alphas
therefore we know 1 gamma = 15/8 alphas or 1 and 7/8 alphas
7____ is the one that couldn't used to complete a table of eqiuvalent ratios
Answer:
8
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 1 • -16 = -16
Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is 6 .
-16 + 1 = -15
-8 + 2 = -6
-4 + 4 = 0
-2 + 8 = 6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and 8
p2 - 2p + 8p - 16
Step-4 : Add up the first 2 terms, pulling out like factors :
p • (p-2)
Add up the last 2 terms, pulling out common factors :
8 • (p-2)
Step-5 : Add up the four terms of step 4 :
(p+8) • (p-2)
Which is the desired factorization
Answer:
B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.
To find the mean absolute deviation, we first find the mean. Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):
(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5
Now we find the difference between each data point and the mean, take its absolute value, and find their sum:
|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =
5+2+2+2+1+1+5+4+3+1 = 26
We now divide this by the number of data points:
26/10 = 2.6
This is a measure of how much each bag of candy varies from the mean.
Answer:
sqrt(35) ≈5.916079783
Step-by-step explanation:
sqrt(35)
35 = 5*7
Neither of these numbers is a perfect square so
sqrt(35) cannot be simplified
it can be approximated
sqrt(35) ≈5.916079783
