Answer:
B) -2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)=(2-(-10))/(-4-2)=(2+10)/-6=12/-6=-2
The algebraic expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)
<em><u>Solution:</u></em>
Given the statement:
Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen
Let us first understand the given statement,
Let the number be "x"
" sum of a number and four" means x + 4
"Three sets of a sum of a number and four" translated to 3(x + 4)
"sum of seven times the same number and thirteen" means 7x + 13
<em><u>Thus the algebraic expression for given statement is:</u></em>

<em><u>Using distributive property in above expression</u></em>

Therefore,

<em><u>Combine the like terms</u></em>

Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)
1. correct- factor: 4
2. correct- factor: 4
3. Incorrect- The polynomial is not prime, and the factored polynomial is 4(2x-3)
4. Incorrect
Converting their ages to months:
12*12=144months + 3 months
=147 months
Now, 3 is equivalent to 147 months;
4 will be equivalent to;
4*147/3
= 196 months
= 16 years and 4 months
Answer:
3x=12
Step-by-step explanation:
3 times X with x being 4 making it 12 so X=4 and 3x=12