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Finger [1]
3 years ago
7

What is the length of YA ?

Mathematics
2 answers:
earnstyle [38]3 years ago
7 0

AYZ is a right triangle (we're given that YA is perpendicular to XZ). So, we can use the pythagorean theorem to find the missing side:

YA^2+AZ^2=YZ^2

But we're also given YZ = 2AZ, so we have

YA^2+AZ^2=(2AZ)^2=4AZ^2

Since AZ is half of YZ, which is 10, we deduce AZ=5.

Solving for YA, we have

YA^2+AZ^2=4AZ^2 \iff YA^2 = 3AZ^2 \iff YA = AZ\sqrt{3} = 5\sqrt{3}

svp [43]3 years ago
7 0

Answer:

A is the answer.

Step-by-step explanation:

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6 0
4 years ago
Solve. 3 A train traveled 936 miles at a constant speed in 12 hours. a. How can you find the number of miles the train traveled
Igoryamba

Answer:

8

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8 0
2 years ago
Convert 9340 m to km
Marina CMI [18]

Answer:

9.34 km

Step-by-step explanation:

  1. m to km = m ÷ 1000
  2. 9340 ÷ 1000 = 9.34

I hope this helps!

7 0
3 years ago
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What is the range of the function?
AleksAgata [21]
The range of the function on the graph is all real numbers greater than or equal to 2 because the range of a function is what the value of y could be, and y begins at 2 and keeps increasing indefinitely.
Hope this helps!

8 0
4 years ago
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An object is launched into the air. The projectile motion of the object can be modeled using the function h(t) = –16t2 + 72t + 5
vladimir2022 [97]

Answer:

Step-by-step explanation:

In the equation, 72t represents the initial upwards velocity and 5 represents the initial launching height.  The leading term represents the pull of gravity on the object in the English system of measurement.

So the first question says the initial height is 5 feet.  TRUE

The second question says the initial vertical velocity is -72.  FALSE (it's positive 72 ft/sec)

The third question says that the object will hit the ground after approximately 4.57 seconds.  TRUE.  Find this by setting the h(t) on the left equal to 0, since this is the height at any time during the flight.  When h(t) = 0, that means that there is NO height, which means the object is on the ground.  Set the equation equal to 0 and factor to find t.  Putting that into the quadratic formula gives you t values of -.068 and 4.57.  Since the 2 things in math that will NEVER EVER be negative are distances and time, we can safely disregard the negative t value and go with t = 4.57.

The fourth question says that after t = 3 seconds, the object is 173 feet high.  FALSE.  Find this by subbing in a 3 for every t in the equation.

h(3)=-16(3)^2+72(3)+5

This gives you that h(3) = 77 feet

The last question says that at t = 0, h(t) = 0.  FALSE again.  Sub in a 0 for every t in the equation, and you get h(0) = 5, which is the initial launching height.

7 0
3 years ago
Read 2 more answers
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