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Bogdan [553]
3 years ago
13

Esme earns a net salary of $2,400 per month. She already has a savings account that has $100 in it. After paying her expenses ev

ery month, she’ll be able to add $100 to her savings account. Esme also plans to purchase a car priced at $20,000 using a no-interest loan. She will make a $300 payment on the loan every month. In how many months will Esme have enough money saved to pay off her loan completely?
A. 44.45 months
B. 45.75 months
C. 47.75 months
D. 49.75 months
E. 50.45 months
Mathematics
1 answer:
Mademuasel [1]3 years ago
3 0

Answer:

D. 49.75 months

Step-by-step explanation:

Esme earns a net salary of $2400 per month.

In her saving account she already have a balance of $100.

She saves $100 every month after her monthly expenses.

She plans to buy a car of $20000 using a no interest loan .

She usually make a $300 payment on the loan every month.

The number of months she will save enough money to pay off her loan completely can be calculated below.

let

x  = number of months

The amount she saved altogether every month is $300 + $100 = $400.

Recall she already has $100 in her account

Amount of loan to be repaid = 100 + 400x

20000 = 100 + 400x

20000 - 100 = 400x

19900 = 400x

divide both sides by 400

x = 19900/400

x = 49.75 months

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eimsori [14]

Answer:

(a) 5^{8}

(b) 3

(c) 27

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Step-by-step explanation:

We need simplify the given expressions.

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Using the properties of exponents we get

(5^4)(5^4)           [\because (a^m)^n=a^{mn}]

5^{4+4}                  [\because a^ma^n=a^{m+n}]

5^{8}

(b)

Consider the given expression is

(9^{\frac{1}{3}})(3^{\frac{1}{3}})

((3^2)^{\frac{1}{3}})(3^{\frac{1}{3}})

Using the properties of exponents we get

(3^{\frac{2}{3}})(3^{\frac{1}{3}})           [\because (a^m)^n=a^{mn}]

3^{\frac{2}{3}+\frac{1}{3}}                 [\because a^ma^n=a^{m+n}]

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(c)

Consider the given expression is

(\dfrac{1}{3})^{-3}

Using the properties of exponents we get

(\dfrac{3}{1})^{3}         [\because a^{-n}=\dfrac{1}{a^n}]

3^{3}

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(d)

Consider the given expression is

(6^4)(6^{-5})

Using the properties of exponents we get

6^{4+(-5)}                  [\because a^ma^n=a^{m+n}]

6^{-1}

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\dfrac{1}{6}  

6 0
3 years ago
Which is an equation of the line that is parallel to the x-axis and that passes through the
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Answer:

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Step-by-step explanation:

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Don't be lazy, use paper or pen, or type it into a calculator!
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5 0
4 years ago
Jennifer serves the volleyball to Marsha with an upward velocity of 10.5 ft/s. The ball is 5 feet above the ground when she stri
Katarina [22]

Answer:

  0.98 seconds

Step-by-step explanation:

We assume the height of the volleyball is described by the equation for ballistic motion. We want to find the time it takes for the height to become zero.

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<h3>motion equation</h3>

The general form of the equation of height for ballistic motion is ...

  h(t)=-16t^2+v_0t+h_0\qquad\text{$v_0$ and $h_0$ are the initial velocity and height}

The coefficient 16 in the equation is an approximation of 1/2g, where g is the acceleration due to gravity in ft/s². This means the units of time and distance are expected to be seconds and feet.

For the problem at hand, the initial velocity and height are 10.5 ft/s and 5 ft. Then the height equation is ...

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<h3>reaction time</h3>

Marsha has until the ball hits the ground to react to the serve. To find out how long that is, we need to solve the height equation for t when h=0. This is most easily done using the quadratic formula with ...

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The solution is ...

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The positive solution is ...

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Marsha has about 0.98 seconds to react before the volleyball hits the ground.

_____

<em>Additional comment</em>

After about 0.33 seconds, Marsha knows she doesn't need to react at all. The serve will not clear the net. Its maximum height is about 6' 8 5/8". A women's volleyball net is 7' 4 1/8" high. Jennifer's serve velocity must be at least 12.3 ft/s for the ball to go over the net. With that upward velocity, Marsha has about 1.06 seconds to react.

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2 years ago
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RUDIKE [14]
The answer is -9
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