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Nadya [2.5K]
3 years ago
10

The list shows the number of stories in the 11 tallest buildings

Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

answer: mode:40 med:30

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When the area in square units of an expanding circle is increasing twice as fast as its radius in linear units
alexira [117]

Answer:

r=1/π

Step-by-step explanation:

Area of the circle is defined as:

Area = πr²

Derivating both sides

\frac{dA}{dr}=2πr

\frac{dA}{dt}  =  \frac{dA}{dr} x \frac{dr}{dt}  =  2πr\frac{dr}{dt}

If area of an expanding circle is increasing twice as fast as its radius in linear units. then we have : \frac{dA}{dt}  =2\frac{dr}{dt}

Therefore,

2πr \frac{dr}{dt}  =  2  \frac{dr}{dt}

r=1/π

5 0
3 years ago
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when table sugar is burned in air, carbon dioxide and water vapor are products, as shown by the following unbalaned chemical equ
Ulleksa [173]
<span>C12H22O11(s)+12O2(g) =12CO2(g)+11H2O(g)</span>
5 0
3 years ago
Please find this answer ​
Semenov [28]

Answer: I cant see the picture so I cant help sorry

Step-by-step explanation:

3 0
2 years ago
Look at the information below. The sum of the measures of angle M and angle R is 90°. © The measure of angle M is (5x + 10). The
kupik [55]

Answer:

Solution given;

<M=5x+10

<R=55

<M+<R=90°

<u>5</u><u>x</u><u>+</u><u>1</u><u>0</u><u>+</u><u>5</u><u>5</u><u>=</u><u>9</u><u>0</u><u>°</u><u>[</u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>equation</u><u>]</u>

<u>now</u><u> </u><u>solving</u><u> </u><u>it</u>

<u>5</u><u>x</u><u>=</u><u>9</u><u>0</u><u>-</u><u>6</u><u>5</u>

<u>5</u><u>x</u><u>=</u><u>2</u><u>5</u>

<u>x</u><u>=</u><u>2</u><u>5</u><u>/</u><u>5</u>

<u>x</u><u>=</u><u>5</u><u>i</u><u>s</u><u> </u><u>your</u><u> </u><u>answer</u><u>.</u>

8 0
2 years ago
Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp
romanna [79]

Answer:

C. 210 miles

Step-by-step explanation:

We have been given that two cars leave Phoenix and travel along roads 90 degrees apart. Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph.

We will use distance formula and Pythagoras theorem to solve our given problem.

\text{Distance}=\text{Speed}\times \text{Time}

\text{Distance covered by Car 1 in 3.5 hours}=\frac{42\text{ Miles}}{\text{Hour}}\times \text{3.5 hour}

\text{Distance covered by Car 1 in 3.5 hours}=147\text{ Miles}.

Since car 1 leaves 30 minutes before car 2, so car 2 will travel for only 3 hours when car 1 will travel for 3.5 hours.

\text{Distance covered by Car 2 in 3 hours}=\frac{50\text{ Miles}}{\text{Hour}}\times \text{3 hour}

\text{Distance covered by Car 2 in 3 hours}=150\text{ Miles}

Since both car travel along roads 90 degree apart, therefore, the distance between both cars after Car 1 has traveled 3.5 hours would be hypotenuse with legs 147 and 150.

\text{Distance between both cars}=\sqrt{147^2+150^2}

\text{Distance between both cars}=\sqrt{21609+22500}

\text{Distance between both cars}=\sqrt{44109}

\text{Distance between both cars}=210.021427\approx 210

Therefore, the both cars will be 210 miles apart and option C is the correct choice.

3 0
3 years ago
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