Solve for j 6j+16=4j-10

Mathematics

2 answers:

prisoha [69]3 years ago

7 0

$\text {Hello! The answer to your problem is j=-13}$

$\text {Subtract 4j:}\\\text {6j+16-4j=4j-10-4j}\\\text {2j+16=-10}$

$\text {Subtract 16:}\\\text {2j+16-16=-10-16}\\\text {2j=-26}$

$\text {DIVIDE both sides by 2:}\\\text {2j/2=-26/2}\\\text {x=-13}$

$\text {Hope this helps!}\\\\\text {-LimitedX}$

Brums [2.3K]3 years ago

3 0

Answer:

j=-13

Step-by-step explanation:

Step 1: Subtract 4j from both sides.

6j+16−4j=4j−10−4j

2j+16=−10

Step 2: Subtract 16 from both sides.

2j+16−16=−10−16

2j=−26

Step 3: Divide both sides by 2.

−26

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1.What is the ratio of v to v max expressed as a percentage when [s] = 30 km

Helga [31]

Answer:

(a)96.77%

(b)3.23%

Step-by-step explanation:

Starting with the Michaelis-Menten equation which is used to model biochemical reactions:

Dividing both sides by $V_{\max }}$

$\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}$

Where: $V_{\max }} =$ maximum rate achieved by the system

$K_{\mathrm {M} }}$ =The Michaelis constant

${\displaystyle {\ce {[S]}}}=$ Substrate concentration

(a) When $[S]=30K_M$

$\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{30K_M}{K_M + 30K_M}\\\dfrac{v}{V_{max}}=\dfrac{30}{1 + 30}\\\dfrac{v}{V_{max}}=\dfrac{30}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{30}{31}X100=96.77\%$

(b)When $K_M=30[S]$

$\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{[S]}{30[S] + [S]}\\\\=\dfrac{1[S]}{30[S] + 1[S]}\\=\dfrac{1}{30 + 1}\\\dfrac{v}{V_{max}}=\dfrac{1}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{1}{31}X100=3.23\%$