Solve for j 6j+16=4j-10

Mathematics

2 answers:

prisoha [69]2 years ago

7 0

$\text {Hello! The answer to your problem is j=-13}$

$\text {Subtract 4j:}\\\text {6j+16-4j=4j-10-4j}\\\text {2j+16=-10}$

$\text {Subtract 16:}\\\text {2j+16-16=-10-16}\\\text {2j=-26}$

$\text {DIVIDE both sides by 2:}\\\text {2j/2=-26/2}\\\text {x=-13}$

$\text {Hope this helps!}\\\\\text {-LimitedX}$

Brums [2.3K]2 years ago

3 0

Answer:

j=-13

Step-by-step explanation:

Step 1: Subtract 4j from both sides.

6j+16−4j=4j−10−4j

2j+16=−10

Step 2: Subtract 16 from both sides.

2j+16−16=−10−16

2j=−26

Step 3: Divide both sides by 2.

−26

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At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen

guajiro [1.7K]

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

$p_1 = \frac{20}{100} = 0.2$