The marginal distribution for gender tells you the probability that a randomly selected person taken from this sample is either male or female, regardless of their blood type.
In this case, we have total sample size of 714 people. Of these, 379 are male and 335 are female. Then the marginal probability mass function would be
![\mathrm{Pr}[G = g] = \begin{cases} \dfrac{379}{714} \approx 0.5308 & \text{if }g = \text{male} \\\\ \dfrac{335}{714} \approx 0.4692 & \text{if } g = \text{female} \\\\ 0 & \text{otherwise} \end{cases}](https://tex.z-dn.net/?f=%5Cmathrm%7BPr%7D%5BG%20%3D%20g%5D%20%3D%20%5Cbegin%7Bcases%7D%20%5Cdfrac%7B379%7D%7B714%7D%20%5Capprox%200.5308%20%26%20%5Ctext%7Bif%20%7Dg%20%3D%20%5Ctext%7Bmale%7D%20%5C%5C%5C%5C%20%5Cdfrac%7B335%7D%7B714%7D%20%5Capprox%200.4692%20%26%20%5Ctext%7Bif%20%7D%20g%20%3D%20%5Ctext%7Bfemale%7D%20%5C%5C%5C%5C%200%20%26%20%5Ctext%7Botherwise%7D%20%5Cend%7Bcases%7D)
where G is a random variable taking on one of two values (male or female).
Answer: The probability is 0.46%.
The chance of each given event happening is 1/6 because there are 6 different number on the dice and only 1 number is chose.
Therefore to find the combined probability, we have to multiply all the individual probabilities.
(1/6) x (1/6) x (1/6)
Or
(1/6)^3
The answer is about 0.46%,
She had spent $78 on books but idk what to do with the book mark cuz it ask for the total # of books not book marks
|-6| + |-3 + (-5)|
6 + |-8|
6 + 8
14
Answer:
38% probability that a randomly selected student is female or a physics major.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Desired outcomes:
Physics majors or female
10 physics majors(of which 3 are female).
12 female(the 3 female physics majors have already been counted, so we count 9)

Total outcomes:
50 students, so 
Probability

38% probability that a randomly selected student is female or a physics major.