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Nastasia [14]
3 years ago
7

Glen is planting square flower gardens surrounding a triangular fishpond as shown. If the sides of the triangular fishpond are 5

ft and 9 ft, how long is the hypotenuse of the pond?
Mathematics
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

h=\sqrt{106} \approx 10.3 feet

Step-by-step explanation:

We will use the Pythagorean Theorem to solve this. Which states that:

One Length^2 + Another Length^2 = Hypotenuse^2

We can take one length as 5 ft and another length as 9 ft and we call the hypotenuse "h", so we have:

5^2+9^2=h^2

Now, let us solve for "h":

5^2+9^2=h^2\\25 + 81 = h^2\\106=h^2\\h=\sqrt{106} \approx 10.3

The pond's hypotenuse is about 10.3 feet

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What is the average rate of change of f(x), represented by the table of values, over the interval [-3,4]
77julia77 [94]

Answer:

Average rate of change = 3

Step-by-step explanation:

  • We know that the average rate of change is basically a measure of the slope of the  secant line  in the closed interval [a, b].

here   a = -3 and b = 4

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⇒ Average rate of change = f(b) - f(a)  / b - a

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Therefore, Average rate of change = 3

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3 years ago
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