All categories

3 years ago

PLEASE HELP ASAP‼️‼️

Mathematics

2 answers:

velikii [3]3 years ago

6 0

Your answer would be C. Architects

taurus [48]3 years ago

5 0

C is the answer to your question

You might be interested in

What is 3 tenths greater than 80%

elena-14-01-66 [18.8K]

we know that

$3$ tenths is equal to

$\frac{3}{10} =0.30$

$80$ % is equal to

$\frac{80}{100} =0.80$

$3$ tenths greater than $80$ % is equal to add

$0.30+0.80=1.10$

therefore

the answer is

$1.10$

6 0

3 years ago

Read 2 more answers

Hi can anybody explain to me how to do this I'm kinda confused . 5×[5(-7)]

telo118 [61]

Answer:

5 × [5(-7)]

= 5 × (-35) ---- 5 × (-7) = -35

= -175

4 0

3 years ago

The perimeter of a triangle is 61 in. The shortest side is 8 in. less than the longest side. The middle side is 19 in. less than

Marianna [84]

Answer:

since the lengths are consecutive odd numbers and the perimeter of the triangle is 51cms. Let x be the unknown length.

so 3x=51 ; x=17 . now the sides can be 15cms, 17cms, 19cms.

check Add them up it is 51cms which is the perimeter and the consecutive odd numbers

6 0

3 years ago

Best explained and correct answer gets brainliest

storchak [24]

The answer is B because they are congruent triangles.

6 0

3 years ago

Read 2 more answers

You travel from point A to point B in a car moving at a constant speed of 70 km/h. Then you travel the same distance from point

tankabanditka [31]

Answer:

Yes, the average speed for the entire trip from A to C is equal to $80\frac{km}{h}$

Step-by-step explanation:

The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time. For the special case of straight line motion in the x direction, the average velocity takes the form:

$V_a_v_e_r_a_g_e=\frac{x_2-x_1}{t_2-t_1}=\frac{Δx}{Δt}$

If the beginning and ending velocities for the motion are known, and the acceleration is constant, the average velocity can also be expressed as:

$V_a_v_e_r_a_g_e=\frac{V_1+V_2}{2}$

We Know that:

$V_1=70\frac{km}{h} \\\\V_2=90\frac{km}{h}$

Replacing the values:

$V_a_v_e_r_a_g_e=\frac{70+90}{2} =\frac{160}{2}=80\frac{km}{h}$

5 0

3 years ago