Let us assume the larger number = x
Let us assume the smaller number = y
Then
x + y = 3 3/4
x + y = 15/4
And
x/3 = (2y/3) + 1/2
x = [3 * (2y/3)] + (3/2)
= 2y + (3/2)
Now putting the value of x from the second equation to the first , we get
x + y = 15/4
2y + (3/2) + y = 15/4
3y = (15/4) - (3/2)
3y = (15 - 6)/4
3y * 4 = 9
12y = 9
y = 9/12
= 3/4
Now putting the value of y in the first equation, we get
x + y = 15/4
x + (3/4) = (15/4)
x = (15/4) - (3/4)
= (15 - 3)/4
= 12/4
= 3
So the value of x or the larger number is 3 and the value of y or the smaller number is 3/4.
First seat: 14 candidates to seat
Second seat: 13 candidates to seat
Third seat : 12 candidates
4th seat: 11 candidates
5th seat: 10 candidates
6th seat: 9 candidates
Number of different variations: 14*13*12*11*10*9 = 2,162,160 different ways,
Observe that is 14P6 = 14! / (14-6)! = 14! / 8! = 14*13*12*11*10*9*8! / 8! =
= 14*13*12*11*10*9
Answer: 2,162,160
Tyler concludes that 5x² will always have a larger output for the same value of x.
<u>Look at the graph below and the table given</u>
Take a random value: x = 0
Here, 1 > 0, making 2^x > 5x²
Hence, 2^x is greater than 5x² at this point. making Tyler's point not applicable.
Disagree with Tyler's point.
Answer:
Count up the side so for 10 count the Arrow going up for the 5 count to the side but like for example.
Go up 10 and move left 5 times?
Does this help
Step-by-step explanation:
Answer:
Step-by-step explanation:
Mp=$1200
Let sp be x
SP=MP-discount% of MP
x=1200-15/100 * 1200
x=120000-18000/100
x=102000/100
x=1020
the amount of money person saves=MP-SP
=$1200-$1020
=$180
therefore he saves $180
