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Harrizon [31]
3 years ago
7

There are 20 bicycles and 10 cars parked in the parking lot. Each bicycle had two wheels and each car had four wheels. How many

wheels are there in total?
wheels?
Mathematics
2 answers:
3241004551 [841]3 years ago
6 0

Answer:

80

Step-by-step explanation:

Inessa05 [86]3 years ago
5 0

Answer:

80

Step-by-step explanation:

(20 x 2) + (10 x 4) = 40 + 40 = 80

brainliest please ;)

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Drake wants to save $750 so that he can take a class on computer analysis for cars. The class is being held on various dates ove
STatiana [176]
C. Both options A and B will allow him to meet his goal.



Looking at Drake's situation after 4 weeks, he only has $470 saved. By his original plan, he should have had $500 saved. So he's $30 short of his goal and has 2 weeks until his originally planned class. If he goes with option A and takes the later class, he will save an additional $125 which is more than enough to make up the $30 short fall. So option A will work for him to save enough money for his class. With option B, he will save $140 for the last 2 weeks of his plan giving him a savings of $280 for the last 2 weeks. Adding the $470 he's already saved will give him a total savings of $470 + $280 = $750 which is enough for him to attend his class. So option B will also allow Drake to attend his desired class. Both options A and B allow him to meet his goal. Hence, the answer is "c".
8 0
3 years ago
Help me please anyone? what is the area of this figure?​
polet [3.4K]
<h2>Answer:</h2><h2>917</h2>

<h3>what you do is that you find the area of the whole thing then you multiply the answer up to get 917</h3>
6 0
2 years ago
a plastering contractor charges $18 per square yard( that is $2 per square foot). what is the cost of plastering 100 feet of wal
Tomtit [17]
Basically, this problem is going to require you to solve for the area and multiply it with the given cost unit.

Area = Length*Height
Area = 100 ft * 8 ft = 800 ft²

Total Cost = (Unit Cost)(Area)
Total Cost = ($2/ft²)(800 ft²)
<em>Total Cost = $1,600</em>
4 0
3 years ago
Find the equation of the circle in standard form for the given center (h, k) and radius R:(H,K)=(4/3,-8/8),R=1/3
Scorpion4ik [409]

Answer:

<h3>The answer is option B</h3>

Step-by-step explanation:

Equation of a circle is given by

( x - h)² + ( y - k)² = r²

where r is the radius and

( h , k) is the center of the circle

From the question the radius R = 1/3

the center ( h ,k ) = (4/3 , -8/3)

Substituting the values into the above equation

We have

(x -  \frac{4}{3} )^{2}  +  {(y -  -  \frac{8}{3}) }^{2}  =  ({ \frac{1}{3} })^{2}

We have the final answer as

(x -  \frac{4}{3} )^{2}  +  {(y  +  \frac{8}{3}) }^{2}  =   \frac{1}{9}

Hope this helps you

7 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
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