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Alexxx [7]
3 years ago
5

Please please help me with this

Mathematics
1 answer:
maks197457 [2]3 years ago
5 0

Answer: 511.8 cm3

3.14x3x5x6x3=847.8

Step-by-step explanation:

16x7x3=336

847.8-336=847.8

Hope I'm right?

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If Δ ABC = Δ DEF, which one of these is a pair of corresponding parts?<br> CB and ED<br> AC and DF
Radda [10]

Answer:

AC and DF

Step-by-step explanation:

Corresponding sides as well as corresponding angles have a pair of same angles or sides that are in the same place in two different shapes that are similar.

Find attached the diagram used for solving the question

Since Δ ABC = Δ DEF

∠B corresponds to ∠E

∠A corresponds to ∠D

∠C corresponds to ∠F

As a result of the above:

Line AB corresponds to line DE

Line AC corresponds to line DF

Line BC corresponds to line EF

Therefore, if Δ ABC = Δ DEF, one of the pair of corresponding parts would be AC and DF.

5 0
3 years ago
there are c cyclist in a cycle race 3/4 of the cyclist finish the race how many cyclist did not finish give a algebraic formula
zimovet [89]

1/4

if 3/4 cyclists finish then that leaves 1/4 of the group that did not finish

4 0
2 years ago
How do you write 15,409 in two ways
bekas [8.4K]
You can write 15,409 like this 10000+5000+400+9 and like this fifteen thousand-four hundred nine
6 0
3 years ago
Read 2 more answers
A hiking trail down the side of Mt. Tom drops a vertical distance of 60 meters over a horizontal distance of 300 meters. What is
Lady_Fox [76]

Answer:

Step-by-step explanation:

Slope of the trail is expressed as;

Slope = vertical distance/horizontal distance

Given

Vertical distance = 60metres

Horizontal distance= 300metres

Substitute

Slope = 60/300

Slope = 6×10/30×10

Slope = 6/30

Slope = 6×1/6×5

Slope = 1/5

Hence the slope of the trail in reduced fraction is 1/5

7 0
3 years ago
Using the Descartes Rule of Signs, describe the real zeroes of the function.
mrs_skeptik [129]

as you already know, Descartes rule of signs check the times the sign changes or f(x) and for f(-x)


\bf \stackrel{\textit{positive roots}}{f(x)=}\underset{change}{2x^5-}x^4\underset{change}{-2x^3+}4x^2\underset{change}{+x-2} \\\\\\ \stackrel{\textit{negative roots}}{f(~-x~)=}-2x^5\underset{change}{-x^4+}2x^3\underset{change}{+4x^2-}x-2


by the fundamental theorem of algebra, the polynomial has a degree of 5, so it has to have at most 5 zeros/solutions/roots.

f(x) has 3 sign changes, notice, that means, it has either 3, or (3-2), 1 positive zeros.

for f(-x), recall that x³, will be (-x)³ = (-x)(-x)(-x) = -x³, so in short, if the exponent is ODD, the sign changes for that term, if it's EVEN, it doesn't change.

so for f(-x), we have 2 sign changes, meaning, it has either 2 or (2-2), 0 negative roots.

the slack is picked up by the complex roots.

so

3 positive, 2 negative, 0 complex

or

1 positive, 2 negative, 2 complex  *recall complex always come in pairs*

or

3 positive, 0 negative, 2 complex

or

1 positive, 0 negative, 4 complex.

5 0
3 years ago
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