What number should be placed in the box to help complete the division calculation?

A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.

zmey [24]

Answer:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=2.2$ represent the sample mean

$s=0.29$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =2.1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.1$

Alternative hypothesis: $\mu > 2.1$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0

3 years ago

Christine purchased a prepaid phone card for $20. Long distance calls cost 18 cents a minute using this card. Christine used her

Luda [366]

Answer:

4 minutes and 32 seconds

Step-by-step explanation:

card $20.00-money left over $15.68 $20.00-$15.68 4.32

6 0

3 years ago

What value or values of x satisfy 2x + 5.31 = 4.2?

Softa [21]

Answer: x can equal -3.2 or -7.4.

Step-by-step explanation:

The correct expression is:

2|x+5.3|=4.2

So, we have an absolute value equation, where it can be positive or negative:

Positive

2 (x+5.3)=4.2

2x+10.6 =4.2

2x=4.2-10.6

2x = -6.4

x= -6.4/2

x = -3.2

Negative

2[-(x+5.3)]=4.2

-2x-10.6 =4.2

-2x= 4.2+10.6

-2x= 14.8

x= 14.8/-2

x= -7.4

x can equal -3.2 or -7.4.

Feel free to ask for more if needed or if you did not understand something.

3 0

3 years ago

How can you write 2,000 in a exponent

Mnenie [13.5K]

1,000 = 10^3 (3 because there are 3 digits after the first one)

2,000 = 2 * 10^3

3 0

3 years ago

the following equation represents the total distance (d) that the Benson family has traveled from their home, after traveling 10

Pani-rosa [81]

Answer:

The distance the Bensons had traveled from their home $3\frac{1}{2}$ hours after picking up their grand parents 292.5 miles

Step-by-step explanation:

The given equation for the distance the Benson family traveled from their home can be presented as follows;

d = 55·t + 100

Where;

d = The total distance that the Benson family has traveled from their home after traveling 100 miles to pick up their grandparents

t = The time duration the Benson family have been traveled from their grandparents home on the way to their vacation

To find how far from their home the Bensons will be after 3 1/2 hours of driving with their grand parents, we substitute t with 3 1/2 hours or 3.5 hours as follows;

d = 55·t + 100

When t = $3\frac{1}{2}$ hours, we get;

$d = 55 \times 3\frac{1}{2} + 100 = 292.5 \ miles$

Therefore, the distance the Bensons had traveled from their home $3\frac{1}{2}$ hours after picking up their grand parents = 292.5 miles.

7 0

3 years ago