0.0285x3=.0855
1.0855x4500=$4884.75 after 3 years
☺☺☺☺
Answer: 420
Step-by-step explanation:
30% of 1400
Gina surveyed students about their lunch time preference. Out of 50 students, 20 prefer eating lunch at 11:00am, 15 prefer eating at 11:15a.m., 10 prefer eating at 11:30a.m. , and 5 have no preference. Based on the information, what is the probability that a student chosen at random has no lunch time preference?
Answer:
$90
Step-by-step explanation:
Given data
Given data
Loss= $13.5
Percentage of the loss= 15%
Let the full loss be x
Hence we can find the value of x as
15/100*x= 13.5
0.15x= 13.5
divide both sides by x
x= 13.5/0.15
x= $90
Hence the loss in full is $90
