Ask question

Ask question

All categories

2 years ago

5

Please help! :)

1 answer:

Olin [163]2 years ago

3 0

Answer:

long term goal is to take on bigger, more challenging targets so I can assess my abilities. I plan on shaping myself during this initial time so that I'm prepared to deliver on bigger targets later. Although I've been in this field for a while now, I haven't been able to utilize my entire set of skills.

Step-by-step explanation:

hope it helps a little idk how to answer that completely

You might be interested in

The frequency distribution chart below represents scores from a math quiz.

Inessa05 [86]

The frequency distribution chart of the math quiz has a data that is skewed left.

<h3>How to interpret the shape of the histogram?</h3>

From the complete question (see attachment for histogram), we have the following highlight:

The dataset on the right-hand side is taller than those on the left.

This means that the dataset is skewed left.

Hence, the statement that best describes the data is (a) The data is skewed left.

Read more about skewness at:

brainly.com/question/27701525

#SPJ1

8 0

2 years ago

2) (-10) + (-7) shoe work

Sladkaya [172]

A negative plus a negative equals a negative so it's just -17

7 0

2 years ago

Find the difference: 11 - 4.7

shutvik [7]

<u><em>Answer: 6.3 *The answer must be have a decimal point.*</em></u>

Explanation:

First, subtract by the numbers. Subtract it's going to be find the difference between the numbers.

$11-4.7=6.3$

You can also add by the numbers.

$6.3+4.7=11$

$11-6.3=4.7$

Hope this helps!

Thank you!

Have a great day!

7 0

2 years ago

Read 2 more answers

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago

Write 2.8 as a mixed number in a simplest form

Elena-2011 [213]

It would be 2 4/5............i hope this helps you

3 0

3 years ago

Read 2 more answers