Not sure what alive by graphing means, but these are the equations on a graph. Red is y=4x+7 and blue is y=-3x.
:^)
Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
Answer:
(-3, 1)
The solution is the point at which both lines intersect.
This is the solution since both lines would have that point and only that ppoint in this type of problem. IN a graph where 2 lines are parralel, there is no solution as they never intersect . on a graph where the 2 lines overlap there is infinite solutions. FInally in a graph like this there is exactly one solution and it is the intersection of both lines
Step-by-step explanation:
where is the figures to solve.
