Question

Given the trinomial x^2-bx-c where both the first and the second signs are negative, the signs of the factors will be:

Answer 1

Answer: both positive

Step-by-step explanation:

Answer 2

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

$x^2-bx-c=0$

Both the first and second signs are negative,

Let α and β are the roots of the $x^2-bx-c=0$,

then, we know that the relationship between the zeroes and coefficients of quadratic equations:

$\alpha+\beta =\frac{-b}{a}=b\\\\and\\\\\alpha \beta =\frac{-c}{a}=-c$

Since the product of roots is positive.

So, the signs of the factors will be one positive and one negative.

Hence, Option 'D' is correct.