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babymother [125]
3 years ago
13

Given the trinomial x^2-bx-c where both the first and the second signs are negative, the signs of the factors will be:

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0

Answer: both positive

Step-by-step explanation:

Blizzard [7]3 years ago
3 0

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

x^2-bx-c=0

Both the first and second signs are negative,

Let α and β are the roots of the x^2-bx-c=0,

then, we know that the relationship between the zeroes and coefficients of quadratic equations:

\alpha+\beta =\frac{-b}{a}=b\\\\and\\\\\alpha \beta =\frac{-c}{a}=-c

Since the product of roots is positive.

So, the signs of the factors will be one positive and one negative.

Hence, Option 'D' is correct.

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ladessa [460]

First, let's find the slope.

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So far our equation looks like: y = 5x + b

Leta plug one of the points into our equation to find b.

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8 0
2 years ago
Simply by using rationalize denominators.<br><br> 2a^-1/2
Advocard [28]
Pemdas, so exponent before multiply
so do a^-1/2 then multiply it by 2

remember that x^ \frac{m}{n}= \sqrt[n]{x^m} and
x^{-m}= \frac{1}{x^m}
therefor, a^ \frac{-1}{2}= \frac{1}{a^ \frac{1}{2} } = \frac{1}{ \sqrt{a} }
the we multiply by 2

\frac{2}{ \sqrt{a} }

8 0
3 years ago
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