3 years ago

(76-x+(17+4x)(25+7x)

Mathematics

2 answers:

daser333 [38]3 years ago

8 0

I believe this is correct

Ivanshal [37]3 years ago

4 0

Answer:

Idk

Step-by-step explanation:

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Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14$

To get the zeros of $f(x)$ , set $y$ or $f(x) =0$

$0=x^3-7x^2-2x+14$

$x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)$

$\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0$

Using the zero factor principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

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solving

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(76-x+(17+4x)(25+7x)​

(76-x+(17+4x)(25+7x)