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sergey [27]
3 years ago
13

I need help on this mathematical problem. thank you!

Mathematics
1 answer:
svp [43]3 years ago
7 0
X*.50= the longer chain
X is how long the first chain is.

It is correct, because they wanted 50% more. More meaning multiply so you would multiply x the first chain times how mor long it needs to be.
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What is the answer to 2+b=7
Natasha_Volkova [10]

Answer:

b=5

Step-by-step explanation:

2+b=7

Subtract 2 from each side

2+b-2=7-2

b= 5

7 0
3 years ago
3y=24 solve by inspection
Ulleksa [173]

Explanation: Division property of equality is dividing both sides of an equation by the same non-zero number does not change the equation.

a÷c=b÷c for c≠0

<u><em>First, you divide by 3 both sides of an equation.</em></u>

<u><em>3y/3=24/3</em></u>

<u><em>Then, simplify.</em></u>

<u><em>24/3=8</em></u>

<u><em>8*3=24</em></u>

<u><em>24/8=3</em></u>

<u><em>y=8 is the final answer.</em></u>

<u><em>Hope this helps!</em></u>

<u><em>Thanks!</em></u>

<u><em>Have a great day!</em></u>

6 0
3 years ago
Read 2 more answers
Which answer choice shows the number of hours in 51/2 days
liq [111]
Hey there,

The answer would be 132 hours..There is 24hours in a day so you multiply 24•5=120 then a half if a day is 12 hours, so you then add 12 to 120 which you get 132..
4 0
3 years ago
Find the value of y for the given value of x.<br> y = x/2 + 9;x = -12
11111nata11111 [884]

Step-by-step explanation:

x = -12

y = x/2 + 9

y = -12/2 + 9

y = -6 + 9

y = 3

4 0
2 years ago
When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither nu
o-na [289]
The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:

x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
3 0
3 years ago
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