Iwould like the answer and the details on a paper

The function h(t)=-4.87t^2+18.75t is used to model the height of an object projected in the air, where h(t) is the height in met

rodikova [14]

Looking at the graph you can see that the domain of the function is:
[0, 3.85]
To find the range of the function, we must follow the following steps:
Step 1)
Evaluate for t = 0
h (0) = - 4.87 (0) ^ 2 + 18.75 (0)
h (0) = 0
Step 2)
find the maximum of the function:
h (t) = - 4.87t ^ 2 + 18.75t
h '(t) = - 9.74 * t + 18.75
-9.74 * t + 18.75 = 0
t = 18.75 / 9.74
t = 1.925051335
We evaluate the function at its maximum point:
h (1.925051335) = - 4.87 * (1.925051335) ^ 2 + 18.75 * (1.925051335)
h (1.93) = 18.05
The range of the function is:
[0, 18.05]
Answer:
Domain: [0, 3.85]
Range: [0, 18.05]
option 1

3 0

4 years ago

Write an equation and solve. Round to the nearest hundredth where necessary. What percent of 24 is 30?

garri49 [273]

30 = 100%

1 = 100/30 = 10/3 %

24 = 10/3 x 24 = 80%

Answer: 80%

7 0

3 years ago

Ayush scored 720 marks out of900. And his brother scored 630 out of 700. whose perfomance is better

tresset_1 [31]

Answer:

in my opinion anush has the better performance

8 0

3 years ago

Read 2 more answers

A random sample of 144 recent donations at a certain blood bank reveals that 81 were type A blood. Does this suggest that the ac

Reptile [31]

Answer:

Null hypothesis: $p=0.4$

Alternative hypothesis: $p \neq 0.4$

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

$\hat p=\frac{81}{144}=0.5625$ estimated proportion of people with type A blood

$p_o=0.4$ is the value that we want to verify

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4$

Alternative hypothesis: $p \neq 0.4$

the statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

3 0

3 years ago

A college student Earned $6500 during summer vacation working as a waiter. The student invested Part of the money at 10% and the

Juliette [100K]

Answer:

The amount invested at 10% rate is $ 2200

Step-by-step explanation:

Given as :

The total amount earn by student = $6500

The total interest received at the end of year = $607

Let the amount invested at 10% rate = $x

So, The amount invested at 9% rate = ($6500 - $x)

Let the time for which money invested = 1 year

<u>Now from Simple Interest method :</u>

SI = $\frac{principal\times Rate\times Time}{100}$

Or, SI_1 + SI_2 = $\frac{x\times 10\times 1}{100}$ + $\frac{(6500-x)l\times 9\times 1}{100}$

Or, SI_1 + SI_2 = $(\frac{10x}{100})+\frac{(6500-x)\times 9}{100}$

Or, $607 × 100 = 10x + (6500-x) × 9

Or, $60700 = 10x- 9x + 58500

Or, $60700 - $58500 = x

Or , 2200 = x

∴ x = 2200

So, The amount invested at 10% rate = $x = $ 2200

Hence The amount invested at 10% rate is $ 2200 Answer

5 0

4 years ago