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3 years ago

Iwould like the answer and the details on a paper

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

5 0

I can't download the picture, you will have to type it out so I can explain it

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Hey, can someone help me?

mel-nik [20]

I would go with 115 is the answer you

7 0

3 years ago

Read 2 more answers

Two regular polygons X and Y are such that the number of sides of X is

anyanavicka [17]

Based on the indices of the regular polygons, the number of sides that X has is 8. See the computation below.

<h3>What is the analysis for the above solution?</h3>

Assuming that X has G number of sides; and

Y has H number of sides, this means that:

G-H = 3 ...........1

Recall that the formula for the exterior angles is:

360/n; where n is number of sides

X = 360/G

Y = 360/H

(360/G) + (360/H) = 117°.......2

Solving 1 and 2 simultaneously, we obtain:

G= 8 and

H = 5

Thus, X has 8 sides.

Learn more about Polygons at:
brainly.com/question/1592456
#SPJ1

4 0

2 years ago

determina la medida de cada uno de los angulos del triángulo ABC si se conoce que (3x+1)° (3x+4)° y (2x-1)°

Triss [41]

Answer:

∠A=67°

∠B=70°

∠C=43°

Step-by-step explanation:

<u><em>The correct question in English is</em></u>

Determines the measurement of each of the angles of the triangle ABC if it is known that A=(3x+1)°,B=(3x+4)° and C=(2x-1)°.

we know that

The measure of the interior angles in a triangle must be equal to 180 degrees

∠A+∠B+∠C=180°

substitute the given values

$(3x+1)\°+(3x+4)\°+(2x-1)\°=180\°$

solve for x

$(8x+4)\°=180\°$

$8x=180-4$

$x=22$

Find the measure of each angle

∠A=(3(22)+1)=67°

∠B=(3(22)+4)=70°

∠C=(2(22)-1)=43°

6 0

3 years ago

HELP AGAIN STILL BEING TIMED

Rama09 [41]

Answer:

Step-by-step explanation:

6 0

3 years ago

Need help with math homework

Pavel [41]

Hello!

The answer for A is:

$X1=-1\\X2=5$

The answer for B is: The rocket will hit the lake surface in 5 seconds.

Defining the terms:

$a=-16\\b=64\\c=80\\$

So, replacing it in the quadratic equation (it's given to you in the exercise)\\

$x=\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}$

$x=\frac{-64+-\sqrt{64^{2}-4*-16*80 } }{2*-16}$

$x=\frac{-64+-\sqrt{64^{2}+5120} }{-32}=\frac{-64+-\sqrt{4096+5120} }{-32}\\x=\frac{-64+-\sqrt{9216} }{-32}=\frac{-64+-\ 96 }{-32}\\x=\frac{-64+-\ 96 }{-32}\\x1=\frac{-64+\ 96 }{-32}=\frac{32}{-32} =-1\\\\x1=\frac{-64-\ 96 }{-32}=\frac{-160}{-32} =5\\$

We are working with a quadratic equation, so we will have two possible results,

$X1=-1\\X2=5\\$

Now, we are asked to find the time, time can not be a negative value, we have to discard X1 (-1) since it's a negative value, knowing that, the rocket will hit the lake after 5 seconds.

Have a nice day!

5 0

4 years ago