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3 years ago

WHOEVER GETS RIGHT GETS BRAINLIEST!!

Mathematics

1 answer:

ozzi3 years ago

3 0

Answer:

Answer B: min. value at -6

Step-by-step explanation:

Complete the square of f(x) = x^2 - 2x - 5.

Note: Please use " ^ " to denote exponentiation, as shown.

Start with f(x) = x^2 - 2x - 5.

Identify the coefficient of the x term: it is 2.

Take half of that and square your result: (1/2)(2) = 1, and then 1^2 = 1.

Add and subtract this 1 between the 2x term and the constant term:

f(x) = x^2 - 2x + 1 - 1 - 5

Rewrite x^2 - 2x + 1 as a perfect square:

f(x) = (x - 1)^2 - 1 - 5, or f(x) = (x - 1)^2 - 6

Compare this to the standard form

f(x) = (x - h)^2 + k

We see that h = 1 and k = -6.

The vertex is located at (h, k); here, it's located at (1, -6).

Thus, the minimum value of this function is at the vertex (1, -6).

This agrees with Answer B: min. value at -6.

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What is 4/15 / -3.4

seraphim [82]

Answer:

Factor the numerator and denominator and cancel the common facotors which would give you 0.07843137

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3 years ago

A(3, -1) and B(6, 0)

Mashutka [201]

Answer:

AB = 3.16 units

Step-by-step explanation:

Given:

A(3, -1) and B(6, 0)

To Find:

AB = ?

Solution:

AB = root{(x2 - x1)^2 + (y2 - y1)^2}

AB = root{(6 - 3)^2 + (0 - (-1))^2}

AB = root{(3)^2 + (0 + 1)^2}

AB = root{9 + (1)^2}

AB = root{9 + 1}

AB = root 10

Therefore, AB = 3.16 units

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3 years ago

Solve the system of equations. 7x+10y=36 y=2x+9 x = ______ y = ______

wel

Step-by-step explanation:

Substitute the y in the 1st equation with the 2nd equation.

7x + 10(2x + 9) = 36

7x + 20x + 90 = 36

27x + 90 = 36

3x + 10 = 4

3x = -6

x = -2

So now we can find y.

y = 2x + 9 = 2(-2) + 9 = (-4) + 9 = 5.

So x = -2, y = 5.

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3 years ago

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What is F(7) if (x) = 5x

Law Incorporation [45]

The answer is 35.
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2 years ago

Read 2 more answers

Let f(x)=x^3-x-1

alexira [117]

$f(x) = x^3 - x - 1$

To find the gradient of the tangent, we must first differentiate the function.

$f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1$

The gradient at x = 0 is given by evaluating f'(0).

$f'(0) = 3(0)^2 - 1 = -1$

The derivative of the function at this point is negative, which tells us the function is decreasing at that point.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

$y = -x + c$

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

$f(0) = (0)^3 - (0) - 1 = -1$

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

$y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}$

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3 years ago