9*(x-1)=2x-7
First get rid of your parenthesis by distributing.
9x-9=2x-7
Then all you have to do is isolate the variable
9x=2x+2
7x=2
so x= 2/7
If you are working with time or days, you can't put in a negative value because if you are doing an experiment, you can't go back in time to do that experiment to gather data. (Time for the most part considered to be an input value so that's why I used it as an example.)
Answer: A. Factor 2 => 4x greater
Factor 3 => 9x greater
Factor 5 => 25x greater
Step-by-step explanation: A. A cylinder is formed by 2 circles and a rectangle in the middle. That's why surface area is given by circumference of a circle, which is the length of the rectangle times height of the rectangle, i.e.:
A = 2.π.r.h
A cylinder of radius r and height h has area:
= 2πrh
If multiply both dimensions <u>by a factor of 2</u>:
= 2.π.2r.2h
= 8πrh
Comparing
to
:
=
= 4
Doubling radius and height creates a surface area of a cylinder 4 times greater.
<u>By factor 3:</u>


Comparing areas:
=
= 9
Multiplying by 3, gives an area 9 times bigger.
<u>By factor 5</u>:


Comparing:
=
= 25
The new area is 25 times greater.
B. By analysing how many times greater and the factor that the dimensions are multiplied, you can notice the increase in area is factor². For example, when multiplied by a factor of 2, the new area is 4 times greater.
Step-by-step explanation:
Area of a circle = #r^2
1256 = 3.14 × r^2
r^2 = 1256/3.14
r^2 = 400
Square root of r = 20
Diameter = 2 × r = 2 × 20 = 40 inches
8 - 8x is already in its simplest form.
Without knowing the value of x, you cannot find what is equivalent to 8 - 8x, but you can it if is an equation, such as 8 - 8x = 88 (x would be -10).
However, you can still rewrite it as -8x + 8, which is equivalent to 8 - 8x.