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NeX [460]
2 years ago
15

a yard width is 2 less than it's length. If the perimeter of the yard is 20 feet determine the length and the width of the yard

Mathematics
1 answer:
Arte-miy333 [17]2 years ago
5 0

Answer:

The length is 6 feet and the width is 4 feet

Step-by-step explanation:

Let x represent the length of the yard

The width can be represented by x - 2, since it is 2 less than the length.

Use the perimeter formula, P = 2l + 2w, where l is the length and w is width

Plug in the expressions and perimeter:

20 = 2x + 2(x - 2)

Solve for x:

20 = 2x + 2x - 4

20 = 4x - 4

24 = 4x

6 = x

So, the length is 6. Plug this into x - 2 to find the width

x - 2

6 - 2

= 4

So, the length is 6 feet and the width is 4 feet

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The answer is c. \frac{46}{9}

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4. We know D is the not the monomial simply because its power is negative which means it does not fit the definition of a polynomial.

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First we have to assume that each quarter touched each other. Hence the area of the table not covered by the coins (A) is equal to the total area of the table (At) minus the total area of the coins (Ac). Coins are circle, so A =  \pi  r^{2} and r =24.26mm. The area of one coin is then 1848.98mm^2. Hence the equation is A = At - xAc where x is the number of coins. 
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