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4 years ago

Terri wrote the equation using slope-intercept form for the line that passes through the points (4, 6) and (–2, 3).

Mathematics

2 answers:

Pavel [41]4 years ago

7 0

Answer:

$y=\frac{1}{2}x+4$

Step-by-step explanation:

Terri wrote the equation using slope-intercept form for the line that passes through the points (4, 6) and (–2, 3)

Using the points find out slope

$slope = \frac{y2-y1}{x2-x1} = \frac{3-6}{-2-4} =\frac{1}{2}$

m= 1/2 and point (4,6)

Use point slope formula

y-y1=m(x-x1)

y-6= 1/2(x-4)

multiply 1/2 inside the parenthesis

y-6= 1/2x - 2

add 6 on both sides

$y=\frac{1}{2}x+4$

oksano4ka [1.4K]4 years ago

4 0

Answer:

y=0.5x+4

Use y2-y1/x2-x1 to find the slope:

3-6/-2-4

Sub in the x and y-values into y=0.5x+b

6=0.5(4)+b

Solve and b=4

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This is so we can get the expression in a(r)^(n-1) form

a = 8/7 is the first term of the geometric sequence
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Note that -1 < 2/7 < 1, which satisfies the condition that -1 < r < 1. This means the infinite sum converges to some single finite value (rather than diverge to positive or negative infinity).

We'll plug those a and r values into the infinite geometric sum formula below

S = a/(1-r)

S = (8/7)/(1 - 2/7)

S = (8/7)/(5/7)

S = (8/7)*(7/5)

S = 8/5

S = 1.6

------------------------

Answer in fraction form = 8/5

Answer in decimal form = 1.6

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