It would be 3 with be on the side and then 2/10
Answer:
Graph A is correct
Step-by-step explanation:
p(x)= x/10
x= 1, 2, 3, 4
Plug in x values in p(x)
when x=1 , then P(1) = 1/10
When x=2 , then P(2) = 2/10
When x=3 , then P(3) = 3/10
When x=4 , then P(4) = 4/10
In the graph y axis has 2/10 , 4/10 , 6/10...
1/10 lies between 0 and 2/10
3/10 lies between 2/10 and 4/10
Graph A is correct
Answer:
v=3i+8j
Step-by-step explanation:
The given the vector v has an initial point (-2,-6) and a terminal point of (1,2).
To find the components of vector v, we subtract the terminal points from the initial point to obtain.
v=<1,2>-<-2,-6>
v=<1--2,2--6>
v=<1+2,2+6>
v=<3,8>
As a linear combination of the standard unit vectors.
v=3i+8j
I will answer second attachment and after since I can't see the firs attachment
2nd attachment
if x is negative, then the first number gets infinitely small
look at the second number, the first 2 is -2 which is wrong since it should be +2
3rd option is not because if x=-2, then y=1
answer is D
3rd attachment
2nd: f(x)=60*1.15^x
3rd: no xint
6th: after 7.86 years value tripples
7th maybe: after 8 years value is 183.51, not exatly 184.00
4th attachment
nth score is
f(n)=57+4(n-1)
9th is
f(9)=57+4(9-1)
57+32=89
answer is C 89
5th
f(t)=23000(1.02)^t
t=time in years from 23000
B could not be the coordinates.
I drew a sketch
