Question

Which function has real zeros at x = 3 and x = 7?

Answer 1

Answer:

Option 3 - $f(x)=x^2-10x+21$

Step-by-step explanation:

To find : Which function has real zeros at x = 3 and x = 7?

Solution :

We have given the roots of the function i.e at x=3 and x=7

So, The factor form is (x-3) and (x-7).

Multiply both the roots to find the function,

$f(x)=(x-3)(x-7)$

$f(x)=x^2-7x-3x+21$

$f(x)=x^2-10x+21$

Therefore, The required function is $f(x)=x^2-10x+21$

So, option 3 is correct.

Answer 2

If it has real zeros at x=3 and 7, the factors of f(x) are:

(x-3)(x-7) so f(x) is

f(x)=x^2-10x+21