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Ghella [55]
3 years ago
5

Solve for x in simplest form. 3=7/2(3x−4)

Mathematics
2 answers:
polet [3.4K]3 years ago
6 0

Answer:

x = 34/21

Step-by-step explanation:

  • 3 = 7/2 (3x-4)
  • 3 = (21/2)x - 28/2
  • 3 = (21/2)x - 14
  • (21/2)x = 17
  • 21x = 34
  • x = 34/21
Verdich [7]3 years ago
4 0

Answer:

x = 34/21

Step-by-step explanation:

3 = 7/2 ( 3 x -4)

We need to perform a multiplication.

The following rule is applied:

In our example, the factors in the new numerator are:

, ,

Notice that all non-fraction factors are placed in the numerator.

The only factor in the new denominator is: 2.

We need to get rid of all the denominators in this equation.

This can be achieved by multiplying both the left and the right side by the Least Common Denominator.

In our example, the LCD is equal to 2.

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(-2/3) / (5/4) =
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8 0
3 years ago
Help asapShape A is congruent to shape ____because a 180° rotation about the origin and then a translation unit(s) right maps sh
Elan Coil [88]

Answer:

Shape A is congruent to shape D and has been translated 2 units to the right

Shape B is congruent to shape E and translated 1 unit to the left.

Step-by-step explanation:

5 0
3 years ago
1. While solutions to the general quintic equation in terms of radicals are impossible to obtain, they do exist. Prove that the
Marta_Voda [28]

Answer:

Step-by-step explanation:

Given is a function as x^5-3x+1

Equating to 0 we have equation

If the function f(x) has x intercepts then the solutions are real

Let us use remainder theorem and change of signs rule

f(0) = 1>0

f(-1) = -1+3+1=3

f(-2) = -32+6+1<0

This implies there is a real root between -1 and -2.

f(1) = -1

Since f(0) and f(1) have different signs, there exists a real root between 0 and 1.

f(2) = 32-6+1>0

Since f(1) and f(2) have different signs there exists a real root between 1 and 2.

Thus there are definitely three real solutions as

one between -1 and 0, one between 0 and 1, and third between 1 and 2.

3 0
4 years ago
Read 2 more answers
Select all of the following true statements if R = real numbers, Z = integers, and W = {0, 1, 2, ...}
scoundrel [369]
We can start solving this problem by first identifying what the elements of the sets really are.

R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.

Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).

W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.

W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.

R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.

0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.

∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are not an element of R).

{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be equal to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).

-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.
5 0
4 years ago
Read 2 more answers
A student writes the equation for a line that has a slope
levacccp [35]
Y = mx + c
Where
y is the y of (2, -8)
x is the x of (2, -8)
m is the gradient or slope
c is the y intercept (you don’t know what it is)

Put into equation and find c

Once find c rewrite the equation with only the m and c in numbers

Eg

y = 5x + 3 (this is an example not the answer)

Hope this is helpful if you don’t understand please comment
7 0
2 years ago
Read 2 more answers
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