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Ghella [55]
3 years ago
5

Solve for x in simplest form. 3=7/2(3x−4)

Mathematics
2 answers:
polet [3.4K]3 years ago
6 0

Answer:

x = 34/21

Step-by-step explanation:

  • 3 = 7/2 (3x-4)
  • 3 = (21/2)x - 28/2
  • 3 = (21/2)x - 14
  • (21/2)x = 17
  • 21x = 34
  • x = 34/21
Verdich [7]3 years ago
4 0

Answer:

x = 34/21

Step-by-step explanation:

3 = 7/2 ( 3 x -4)

We need to perform a multiplication.

The following rule is applied:

In our example, the factors in the new numerator are:

, ,

Notice that all non-fraction factors are placed in the numerator.

The only factor in the new denominator is: 2.

We need to get rid of all the denominators in this equation.

This can be achieved by multiplying both the left and the right side by the Least Common Denominator.

In our example, the LCD is equal to 2.

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Gnom [1K]
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3 years ago
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Determine how many solutions if correct bainliest​
PolarNik [594]

Answer:

No solutions

Step-by-step explanation:

6x+2y=20

-3x-y=-4 (by rewriting)

So

6/-3 = 2/-1≠20/-4

-2=-2≠-5

So it has no solutions

5 0
3 years ago
Find the marginal profit of C(x)=5x^2, R(x)=x^3+7x+10 and find all values of x for which the marginal profit is zero.
jonny [76]
Marginal profit, P(x) = R(x) - C(x)

P(x) = x³ - 5x² + 7x + 10

x³ - 5x² + 7x + 10 = 0
If you solve it, you get x = -0.839 where P(x) is zero

4 0
3 years ago
How do you write 1 hundred 25tens 1one ??
My name is Ann [436]
I think it would be 1251 
7 0
3 years ago
Read 2 more answers
Help pleaseeeeeeeeeeeeeeeeeeeeeee
bixtya [17]

Answer:  \bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}

<u>Step-by-step explanation:</u>

(1)           (12, 18, 27, ...)

The common ratio is:

r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\  r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}

(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad  r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\  r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}

3 0
3 years ago
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