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Vilka [71]
3 years ago
8

Essay tests tend to focus on debate and discussion of material covered. Please select the best answer from the choices provided

T F
Advanced Placement (AP)
2 answers:
bazaltina [42]3 years ago
5 0

Answer:

True

Explanation:

These two areas are the main focus of essay tests. Essays are long texts that put forward a particular view or way of thinking, and defend it. This particular view is the thesis, and the thesis usually comes from the material that we you have covered in class. Essays also focus on debate, as they defend this particular point of view over others. During an essay test, you are usually asked to write an essay that fulfills these requirements.

Volgvan3 years ago
4 0
True, essays usually give you a choice of 2 sides, and asks which one you 'prefer' or think is the best of both, and to defend your side, and "bash down" the other one

hope this helps
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High school is secondary school
irina [24]

Answer:

A secondary school locally may be called high school or senior high school.

Explanation:

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3 years ago
Surface Area of a can is 517.8 cm^2. Maximize the volume of this can using the measured surface area.
mafiozo [28]

Answer:

r = 5.24 --- Radius

h = 10.48 --- Height

Explanation:

Given

Object: Can (Cylinder)

Surface\ Area = 517.8cm^2

Required

Maximize the volume

The surface area is:

S.A = 2\pi r^2 + 2\pi rh

Substitute 517.8 for S.A

517.8 = 2\pi r^2 + 2\pi rh

Divide through by 2

258.9 = \pi r^2 + \pi rh

Factorize:

258.9 = \pi r(r + h)

Divide through by \pi r

\frac{258.9}{\pi r} = r + h

Make h the subject

h = \frac{258.9}{\pi r} - r --- (1)

Volume (V) is calculated as:

V = \pi r^2h

Substitute (1) for h

V = \pi r^2(\frac{258.9}{\pi r} - r)

Open Bracket

V = 258.9r - \pi r^3

Differentiate V

V' = 258.9 - 3\pi r^2

Set V' to 0

0 = 258.9 - 3\pi r^2

Collect Like Terms

3\pi r^2 = 258.9

Divide through by 3

\pi r^2 = 86.3

Divide through by \pi

r^2 = \frac{86.3}{\pi}

r^2 = \frac{86.3*7}{22}

r^2 = \frac{604.1}{22}

Take square root of both sides

r = \sqrt{\frac{604.1}{22}

r = 5.24

Recall that:

h = \frac{258.9}{\pi r} - r

Substitute 5.24 for r

h = \frac{258.9}{\pi * 5.24} - 5.24

h = \frac{258.9*7}{22 * 5.24} - 5.24

h = \frac{1812.3}{115.28} - 5.24

h = 15.72 - 5.24

h = 10.48

Hence, the dimension that maximize the volume is:

r = 5.24 --- Radius

h = 10.48 --- Height

7 0
3 years ago
Awad
Shkiper50 [21]

Answer:

1)it's $12.09

2) it's 8.48

but if you want the total of both of them it is $20.47

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Sloan [31]

Answer: True

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What are extrinsic values
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