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Dahasolnce [82]
3 years ago
10

Part A: Determine if the expression is one of our special products. If so, identify it by its general form:

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
8 0

Answer:

1.

Part A: Yes, it is (a - b)².

Part B: a² - 2ab + b² => (x - 6)² = x² - 12x + 36.

Part C: x² - 12x + 36.

2.

Part A: Not a special product.

Part B: Binomial distribution => (x + 8)(x + 1) = x² + 9x + 8.

Part C: x² + 9x + 8.

3.

Part A: Yes, it is (a + b)²

Part B: a² + 2ab + b² => (3x + 2)² = 9x² + 12x + 4.

Part C: 9x² + 12x + 4.

4.

Part A: Yes, it is (a + b)(a - b), a difference of squares.

Part B: a² - b² => 4x² - 49

Part C: 4x² - 49.

5.

Part A: Not a special product.

Part B: Binomial distribution => (x - 5)(2x - 5) = 2x² - 15x + 25.

Part C: 2x² - 15x + 25.

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I DONT KNOW THESE! HELP!
kkurt [141]

Answer:

20. x = 5, y = -2

21. x = 11, y = 12

22. x = 22, y = 11

23. x = 11, y = 10

Step-by-step explanation:

20. Opposite sides in the parallelogram are congruent, so

2y+18=3x-1\\ \\6x-3=17-5y

Solve this system of two equations:

\left\{\begin{array}{l}2y-3x=-19\\ \\6x+5y=20\end{array}\right.

Multiply the first equation by 2 and add two equations:

2(2y-3x)+6x+5y=2\cdot (-19)+20\\ \\4y-6x+6x+5y=-38+20\\ \\9y=-18\\ \\y=-2

Substitute it into the first equation:

2\cdot (-2)-3x=-19\\ \\-3x=-19+4\\ \\-3x=-15\\ \\x=5

21. Opposite angles in the parallelogram are congruent, so

11x+5=10y+6

Consecutive angles are supplementary, so

6x-y+11x+5=180^{\circ}

Solve this system of two equations:

\left\{\begin{array}{l}11x-10y=1\\ \\17x-y=175\end{array}\right.

From the second equation

y=17x-175

Substitute it into the first equation:

11x-10(17x-175)=1\\ \\11x-170x+1750=1\\ \\-159x=-1749\\ \\x=11\\ \\y=17\cdot 11-175=187-175=12

22. Opposite angles in the parallelogram are congruent, so

2x-5=3y-12

Consecutive angles are supplementary, so

2x-5+7y+x=180^{\circ}

Solve this system of two equations:

\left\{\begin{array}{l}2x-3y=-7\\ \\3x+7y=185\end{array}\right.

From the first equation

x=-3.5+1.5y

Substitute it into the second equation:

3(-3.5+1.5y)+7y=185\\ \\-10.5+4.5y+7y=185\\ \\-105+45y+70y=1,850\\ \\115y=1,850+105\\ \\115y=1,955\\ \\y=17\\ \\x=-3.5+1.5\cdot 17=22

23. Opposite sides in the parallelogram are congruent, so

2x+9=4y-9\\ \\3x-5=2y+8

Solve this system of two equations:

\left\{\begin{array}{l}2x-4y=-18\\ \\3x-2y=13\end{array}\right.

Multiply the second equation by 2 and subtract it from the first equation:

2x-4y-2(3x-2y)=-18-2\cdot 13\\ \\2x-4y-6x+4y=-18-26\\ \\-4x=-44\\ \\x=11

Substitute it into the first equation:

2\cdot 11-4y=-18\\ \\-4y=-18-22\\ \\-4y=-40\\ \\y=10

3 0
3 years ago
The figure below shows square ABCD inscribed on square PQRM on a coordinate plane. Which of the following expressions represents
vova2212 [387]
The hypotenuse of the triangle is given by:
 CB ^ 2 = RC ^ 2 + RB ^ 2

 Substituting values:
 CB ^ 2 = 2 ^ 2 + 4 ^ 2

 Clearing CB we have:
 CB = \sqrt{ 2 ^ 2 + 4 ^ 2}  

 CB = \sqrt{ 4 + 16}  

 CB = \sqrt{20}  

 CB = \sqrt{4*5}  

 CB = 2\sqrt{5}  




 Then, the perimeter of the triangle is:
 P = RB + RC + CB

 Substituting values:
 P = 4 + 2 + 2 \sqrt{5} 

 P = 6 + 2 \sqrt{5}
 Answer:
 the perimeter of triangle BRC in units is:
 D.6 + 2√5
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Answer:

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Step-by-step explanation:

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Evaluate 8a - 1 + 0.5b when a= 1/4 and b=10.
nikitadnepr [17]

Answer:

6

Step-by-step explanation:

Substitute 1/4 with 8a. 8/4=2

Next, Substitute 10 for 0.5. 10/2=5

Finally, find the sum

(2-1)+5

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2 years ago
Work out the answer to 1 ⅔÷¾ ​
lisabon 2012 [21]

Answer:

flip the last fraction and cross mutiply, then mutiply regular

Step-by-step explanation:

6 0
3 years ago
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