Let a = weight of large box in pounds
Let b = weight of small box in pounds
(1) 65a + 70b=4000
(2) a+b=60
Now we can simultaneously solve these equations.
a = 60 - b. Hence 65(60 - b) + 70b = 4000 So 3900 + 5b = 4000 and 100 = 5b hence b = 20.
SImilarly a = 40. Now we can verify too by putting in the calculated values.
Cos (π/2 - x) = sin x = 3/5
tan x = sin x / cos x = 3/5 / 4/5 = 3/4
csc x = 1/sin x = 1 / 3/5 = 5/3
sec x = 1/cos x = 1 / 4/5 = 5/4
cot x = 1/tan x = 1 / 3/4 = 4/3.
Answer:
1
Step-by-step explanation:
Using the trigonometric identities
tan(90 - x) = cotx , cotx = 
Given
tan1tan2tan3....................... tan87tan88tan89
= tan1tan2tan3............... tan(90-3)tan(90-2)(tan90 - 1)
= tan1tan2tan3.............. cot3cot2cot1
= tan1cot1tan2cot2tan3cot3 ........................
= 1 × 1 × 1 ×....................... × 1
= 1
Let's look at an example.
We'll add the fractions 1/6 and 1/8
Before we can add, the denominators must be the same.
To get the denominators to be the same, we can...
- multiply top and bottom of 1/6 by 8 to get 8/48
- multiply top and bottom of 1/8 by 6 to get 6/48
At this point, both fractions involve the denominator 48. We can add the fractions like so
8/48 + 6/48 = (8+6)/48 = 14/48
Add the numerators while keeping the denominator the same the entire time.
The last step is to reduce if possible. In this case, we can reduce. This is because 14 and 48 have the factor 2 in common. Divide each part by 2.
The fraction 14/48 reduces to 7/24
Overall, 1/6 + 1/8 = 7/24
Answer:
The largest possible value of n is 11.
(A) is correct option.
Step-by-step explanation:
Given that,
The number with at least two digits,the last number was removed. The resulting number was n smaller than the previous one.
We need to find the largest possible value of n
Using given data,
The smallest number of two digit is 10.
Now, we removed last digit then we get 1 which is equal to 10 divided 10.
So, n = 10
But the largest number of two digit is 99.
We removed last digit then we get 9 which is equal to 99 divided 11.
So, n = 11
Hence, The largest possible value of n is 11.
(A) is correct option.