8.9-3.3j=-2.2j+2.3
add 3.3j to both sides
8.9=1.1j+2.3
subtract 2.3 from both sides
6.6=1.1j
divide both sides by 1.1
6=j
Answer:
r = π C , C = 12 − x , t h e n r = π ( 12 − x ) = 12 π − π x
Step-by-step explanation:
So cutting the wire of 12 m in length into two pieces, x and 12-x. The x side will be made into the square so that the square has sides x/4 and an area of (x/4)^2. This means the length of the wire 12-x will be the circumference of the circle. So if: r = π C , C = 12 − x , t h e n r = π ( 12 − x ) = 12 π − π x i hope this is correct
In a sample of digits(0,1,2,3,4,5,6,7,8,9,) what is the probability that a digit is 7 or greater
ad-work [718]
Answer:
Step-by-step explanation:
There are 10 numbers in total. Only three are 7 or greater: 7, 8, 9.
So the answer is .
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Multiply the number in the tens place of the bottom
number by the number in ones place of the top number. So
multiply the 1 by the 5, which makes 5. Multiply the number in
the tens place of the bottom number by the number in tens
place of the top number. Multiply 1 by 2, which equals 2.
