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e-lub [12.9K]
3 years ago
9

Determine the first five iterates of f(x)=1.5x(1-x) for x0=0.8

Mathematics
1 answer:
kherson [118]3 years ago
3 0
<span>f(x) = 1.5 x (1 - x)
f(0.8) = 1.5(0.8)(1 - 0.8) = 0.24
f(0.24) = 1.5(0.24)(1 - 0.24) ~= 0.274
f(0.274) = 1.5(0.274)(1 - 0.274) ~= 0.298
f(0.298) = 1.5(0.298)(1 - 0.298) ~= 0.314
f(0.314) = 1.5(0.314)(1 - 0.314) ~= 0.323

</span>So the answer is D : 0.24, 0.274, 0.298, 0.314, 0.323
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Answer:

x=\frac{275}{62} , y=\frac{127}{31}

Step-by-step explanation:

<h3>I will use the elimination method.</h3>

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Substitute y into either equation 1 or 2:

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2 years ago
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Answer:

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Step-by-step explanation:

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Then, use the quadratic formula to find the solutions. The quadratic formula looks like\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}.

For this problem, the quadratic variables are as follows:

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The next step is to substitute the values a=1, b=32, and c=244 into the quadratic formula and solve. The quadratic formula will look like \frac{-32(+-)\sqrt{32^2-4(1*244)} }{2*1}. To simplify the equation, start by simplifying the numerator, which will look like x=\frac{-32(+-)4\sqrt{3} }{2*1}. Then, multiply 2 by 1 and simplify the equation, which will look like x=-16(+-)2\sqrt{3}. The final answer is x=-16 ±2\sqrt{3} in exact form. In decimal form, the final answer is x=-12.535898, x=-19.464102.  

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