In order to reduce ANY fraction to lowest terms, find any common factors
of the numerator and denominator, and divide them both by it. If they still
have a common factor, then divide them by it again. Eventually, they won't
have any common factor except ' 1 ', and then you'll know that the fraction is
in lowest terms.
Do 15 and 40 have any common factors ?
Let's see . . .
The factors of 15 are 1, 3, <em>5</em>, and 15 .
The factors of 40 are 1, 2, 4,<em> 5</em>, 8, 10, 20, and 40 .
Ah hah ! Do you see that ' <em>5</em> ' on both lists ? That's a common factor.
So 15/40 is NOT in lowest terms.
Divide the numerator and denominator both by 5 :
15 / 40 =<em> 3 / 8</em>
3 and 8 don't have any common factor except ' 1 '.
So 3/8 is the same number as 15/40, but in lowest terms.
You find the answer through the Pythagorean theorem
a^2 + b^2 = c^2 a & b are the legs and c is the hypotenuse
a = 40
b = ?
c = 41
40^2 + b^2 = 41^2
1600 + b^2 = 1681
b^2 = 1681 - 1600
b^2 = 81
b = 9
the length of the other leg is 9
i hope you found this helpful!
The formula for calculating length is:
![\sqrt{ (x_b-x_a)^{2} + (y_b-y_a)^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%28x_b-x_a%29%5E%7B2%7D%20%2B%20%28y_b-y_a%29%5E%7B2%7D%20%7D%20)
We can also write
![x_a - x_b](https://tex.z-dn.net/?f=%20x_a%20-%20x_b%20)
or
![y_a - y_b](https://tex.z-dn.net/?f=%20y_a%20-%20y_b%20)
Why it does not matter?
Let's assume we have 2 numbers, a and b.
When we perform a subtraction:
![a-b](https://tex.z-dn.net/?f=%20a-b%20)
, we get another number
![c](https://tex.z-dn.net/?f=%20c%20)
When we perform another subtraction:
![b-a](https://tex.z-dn.net/?f=%20b-a%20)
, we get a number
![-c](https://tex.z-dn.net/?f=%20-c%20)
When we raise
![c](https://tex.z-dn.net/?f=%20c%20)
or
![-c](https://tex.z-dn.net/?f=%20-c%20)
to the power of 2, the result is the same,
![c^{2}](https://tex.z-dn.net/?f=%20c%5E%7B2%7D%20)
.
Answer:
Step-by-step explanation:
Margin of Error = Zcritical * Standard error
Zcritical at 5% confidence interval
Z0.065