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3 years ago

CORRECT ANSWERS WILL GET 30 POINTS!!! PLEASE HELP

Mathematics

2 answers:

irakobra [83]3 years ago

6 0

Answer:

sqrt of 1000= 31.6m

A=pi r2

1000pi= pi r2 (pi cancels)

1000=r2 (take square root of both sides)

r= 31.6m

Step-by-step explanation:

Vlad [161]3 years ago

4 0

R=31.6m is the answer

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at the conrad bakery plant 200 employees each worked 5 hours overtome this wee. each employee has a regular wage of 9.40 an hour

dezoksy [38]

Regular pay = $9.40
Overtime pay = 9.4 x 1.5 = $14.10

1 hour = 14.10
5 hours = 14.10 x 5 = $70.50

1 employee = $70.50
200 employees = 70.50 x 200 = $14100

7 0

3 years ago

For any value of x, the sum <br> 3<br> ∑ k(2x-1) <br> k=0<br> is equivalent to

MArishka [77]

The equivalent value of the sum for any value of "x" is 12x - 6

<h3>How to find the sum of functions?</h3>

Given the sum of the expression as:

∑ k(2x-1)

k=0

We need to take the sum of the function at the point where k = 0 to 3

∑ k(2x-1) = 0(2x-1) + 1(2x - 1) + 2(2x-1) + 3(2x - 1)

k=0

∑ k(2x-1) = 2x-1+4x-2+6x-3

k=0

∑ k(2x-1) = 12x - 6

k=0

Hence the equivalent value of the sum for any value of "x" is 12x - 6

Learn more on sum functions here: brainly.com/question/24295771

8 0

2 years ago

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

3 years ago

Please answer it now in two minutes

Nikitich [7]

Answer:

3√6

Step-by-step explanation:

tan60=opp/adj

opp(d)=tan60*3√2=√3*3√2=3√6

7 0

3 years ago

Hey i need help please

Papessa [141]

255.is the answer because of the 38 and the 48 percent of each of both the x and y and is you add then times them you get 255 as your answer

5 0

3 years ago