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katovenus [111]
3 years ago
5

I'm not good with ordering fractions from smallest to largest. Can help anyone help with this problem?

Mathematics
1 answer:
ziro4ka [17]3 years ago
3 0
5/8,4/6,3/4,1/2 this is the answer without simplifying
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Hi, can someone explain to me what Constant of proportionality is using an example problem because I don't understand it.
juin [17]

Answer:

The constant of proportionality is the ratio between two directly proportional quantities. Two quantities are directly proportional when they increase and decrease at the same rate. The constant of proportionality k is given by k=y/x where y and x are two quantities that are directly proportional to each other.

4 0
3 years ago
V(x)=x^2-25
Whitepunk [10]

Answer:

  -∞ < x < -5 ∪ -5 < x < -3/2 ∪ -3/2 < x < ∞

Step-by-step explanation:

The domain of any polynomial is "all real numbers." The domain of any rational function excludes any values of the variable that result in the denominator being 0. The function is "undefined" there.

__

  v(x)=\dfrac{x^2-25}{2x^2+13x+15}=\dfrac{(x+5)(x-5)}{(x+5)(2x+3)}\qquad x\notin \{-5,-\dfrac{3}{2}\}

The values x=-5 and x=-3/2 make the denominator of v(x) become 0, so those values are excluded from the domain of v(x). The function is "undefined" when its denominator is zero.

  -∞ < x < -5 ∪ -5 < x < -3/2 ∪ -3/2 < x < ∞

_____

<em>Additional comment</em>

The numerator and denominator factors (x+5) cancel each other, so there is no vertical asymptote at x=-5. Rather, the function has a "hole" there, where it is undefined. The limit as the function approaches x=-5 from either direction is v(x) = 10/7.

7 0
2 years ago
Solve.<br><br> x^-9 y^3 / x^-7 y^8
aniked [119]

\dfrac{x^{-9}y^3}{x^{-7}y^8}=x^{-9-(-7)}y^{3-8}=x^{-2}y^{-5}=\dfrac{1}{x^2y^5}\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}

3 0
4 years ago
Solve by the addition method ( elimination). <br> 5x+2y=-17<br> 3x-2y=-7
zzz [600]
<span>A) 5x + 2y= -17
B) 3x -2y = -7
Adding the 2 equations, we get
8x = -24
x = -3
</span><span>B) 3*-3x -2y = -7
-9 - 2y = -7
2y = -2
y = -1

</span>
6 0
4 years ago
What is the square root of 36x to the fourth power?
-BARSIC- [3]
\sqrt{36x^4}=\sqrt{36}\cdot\sqrt{x^4}=\sqrt{6^2}\cdot\sqrt{(x^2)^2}=6\cdot x^2=\boxed{6x^2}
8 0
4 years ago
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