Question

Find the indicated values, where

Answer 1

Answer:

b. 0

Step-by-step explanation:

Given: g(t) = t^2 - t and f(x) = 1 + x

Let's find f(3) and f(1)

f(3) = 1 + 3 = 4

f(1) = 1 + 1 = 2

Now we have to plug in these values, we get

g(f(3) - 2f(1)) = g(4 - 2(2))

= g(4 - 4)

= g(0)

g(0) = 0^2 - 0

g(0) = 0

The value of is b. 0

Hope you will understand the concept.

Thank you.

Answer 2

Answer:

option (b) is correct.

The value of $g(f(3)-2f(1))$  is 0.

Step-by-step explanation:

Given: $g(t)=t^2-t$ and $f(x)=1+x$

We have to find the value of $g(f(3)-2f(1))$

Consider the given function $f(x)=1+x$

First evaluate value of function f(x) at x = 3 and 1 then substitute it in $g(f(3)-2f(1))$ .

f(3) = 1 + 3 = 4

f(1) = 1 + 1 = 2

Substitute, we get

$g(f(3)-2f(1))=g(4-2(2))$

Solving further , we get,

 $g(f(3)-2f(1))=g(4-4)=g(0)$

Now evaluate $g(t)=t^2-t$ at t = 0 , we get,

$g(0)=0^2-0=0-0=0$

Thus, value of $g(f(3)-2f(1))$  is 0.

Thus, option (b) is correct.