Question

Object A travels in the +x-direction before hitting a stationary object B. Afterwards, object AÍs x-momentum is 5.7 _ 104 kilogram meters/second and its y-momentum is 6.2 _ 104 kilogram meters/second. What is the objectÍs resultant angle of motion with the +x-axis after the collision?

Answer 1

Below are the choices that can be found from other sources:

A. 42 
B. 45 
C. 47 
D. 48 
E. 49

The answer is C or 47. The object’s resultant angle of motion with the +x-axis after the collision is  47. The reason for that is from object A’s x-momentum is 5.7 × 104 kilogram meters/second and its y-momentum is 6.2 × 104 kilogram meters/second, we know that tan of the angle from the x-axis is 6.2 / 5.7 = 1.09 and acrtan 1.09 = 47.4

Answer 2

Answer:

The object’s resultant angle of motion with the +x-axis after the collision is 47 .

Step-by-step explanation:

It is given that Object A travels in the +x-direction before hitting a stationary object B. From object A’s x-momentum is $5.7{\times}10^4kgms^{-1}$ and its y-momentum is $6.2{\times}10^4kgms^{-1}$.

We know that tan of the angle from the x-axis is given as:

$tanx=\frac{5.7{\times}10^4}{6.2{\times}10^4}$

$tanx=\frac{5.7}{6.2}$

$tanx=1.09$

$x=tan^{-1}(1.09)$

$x=47.4$

Therefore, The object’s resultant angle of motion with the +x-axis after the collision is 47 .