Question

What is the 2010th letter in the following sequence: ABCDEDCBA.

Answer 1

Answer:

B

Step-by-step explanation:

The sequence is ABCDEDCBABCDEDCBABCDEDCBA....

⇒The main sequence is the repitition of the sub-sequence ABCDEDCB

2010 when divided by 8 gives a quotient of 251 and a remainder of 2

251×8 = 2008

This means that after the sub-sequence ABCDEDCB is repeated for 251 times, it's last letter B is the $2008^{th}$ letter of the main sequence

Even after that, the sub-sequence ABCDEDCB keeps repeating and the $2010^{th}$ letter in the main sequence is the $2^{nd}$ letter of the sub-sequence ABCDEDCB, that is "B"