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BabaBlast [244]
3 years ago
7

Determine if the given set is a subspace of set of prime numbers P 9. Justify your answer. The set of all polynomials of the for

m p​(t)equalsat Superscript 9​, where a is in set of real numbers R. Choose the correct answer below. A. The set is not a subspace of set of prime numbers P 9. The set is not closed under multiplication by scalars when the scalar is not an integer. B. The set is a subspace of set of prime numbers P 9. The set contains the zero vector of set of prime numbers P 9​, the set is closed under vector​ addition, and the set is closed under multiplication by scalars. C. The set is not a subspace of set of prime numbers P 9. The set does not contain the zero vector of set of prime numbers P 9. D. The set is a subspace of set of prime numbers P 9. The set contains the zero vector of set of prime numbers P 9​, the set is closed under vector​ addition, and the set is closed under multiplication on the left by mtimes9 matrices where m is any positive integer.
Mathematics
1 answer:
Valentin [98]3 years ago
5 0

Answer: C. The set is not a subspace of set of prime numbers P 9. The set does not contain the zero vector of set of prime numbers P 9.

Step-by-step explanation:

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navik [9.2K]
Simplify the following:
(5 i^3 t^4)/7 - 2
i^3 = i^2×i = (-1) i = -i:
(5×-i t^4)/7 - 2
Put each term in (5 (-i) t^4)/7 - 2 over the common denominator 7:
(5 (-i) t^4)/7 - 2 = (-5 i t^4)/7 - 14/7:
(-5 i t^4)/7 - 14/7
(-5 i t^4)/7 - 14/7 = (-5 i t^4 - 14)/7:
Answer:  (-5 i t^4 - 14)/7
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3 years ago
Graph x &gt; -3x&gt;−3x, is greater than, minus, 3.
antiseptic1488 [7]
It just is :). Ok ok
4 0
3 years ago
Please answer this correctly.
Ganezh [65]

Answer:

The given function is a nonlinear function because the degree of the function is 2 and we get same value of y for more than one values of x.

Step-by-step explanation:

The given function is

y=2x^2-5

To find the points which lie on the function, put difference values of x in the given function and find the values of y.

Put x= -2

y=2(-2)^2-5=2(4)-5=8-5=3

Put x= -1

y=2(-1)^2-5=2(1)-5=2-5=-3

Put x= 0

y=2(0)^2-5=2(0)-5=-5=-5

Put x=1

y=2(1)^2-5=2(1)-5=2-5=-3

Put x= 2

y=2(2)^2-5=2(4)-5=8-5=3

The table of values is shown below.

Plot these points on a coordinate plane and connect them by a free hand curve.

The given function is a nonlinear function because the degree of the function is 2 and we get same value of y for more than one values of x.

The graph of function is shown below.

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3 years ago
M is the midpoint of AB.<br> AM = = 4x - 8<br> MB =<br> 5x-3/3<br> Find x and AB
marusya05 [52]
X=-7 AB=-72

steps

since m is a midpoint, AM and MB are congruent so you set the two equations equal to each other, 4x-9=5x-3/3( is this a typo? bc 3/3 is 1)
subtract 4x from both sides m, -8=x-1
add 1 to both sides
x=-7

then plug -7 in for x 4(-7)-8=-36
since the two segments are congruent u do -36 x 2= -72
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The diagram shows a sector of a circle of radius 4 cm.<br> work out the length of the arc abc
Zielflug [23.3K]
Need to know the angle for this I think?
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