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3 years ago

Rewrite the function f(x) = -2(x+3)^2 – 8 in the form f (x) = ax²+bx+c.

Mathematics

1 answer:

OverLord2011 [107]3 years ago

8 0

Answer:

-2x^{2}-12x-26

Step-by-step explanation:

(x+3)^2 = x^2+6x+9

-2(x^2+6x+9)-8

-2x^2-12x-18-8

-2x^2-12x-26

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Solve the equation 2(x-4)=-22

Tcecarenko [31]

Hello Lexi!

<u><em>Answer: ⇒⇒⇒⇒⇒⇒ $x=-7$ </em></u>

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Step-by-step explanation:

First you had to divide by 2 from both sides of equation.

$\frac{2(x-4)}{2}=\frac{-22}{2}$

Simplify.

$\frac{2(x-4)}{2}=x-4$

$\frac{2(x-4)}{2}$

Divide by the numbers.

$\frac{2}{2}=1$

$=x-4$

$\frac{-22}{2}=-11$

Apply the fraction rule.

$\frac{-22}{2}$

$=-\frac{22}{2}$

Then you divide by the number.

$\frac{22}{2}=11$

$=-11$

$x-4=-11$

Add by 4 from both sides of equation.

$x-4+4=-11+4$

Simplify it should be the correct answer.

$x=-7$

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Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

-Charlie

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3 years ago

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What number is 13% of 52

MaRussiya [10]

$13 \% \ of \ 52= \frac{13}{100}*52= 13*0.52= \boxed{6.76}$

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3 years ago

I need help on this question

tatiyna

It is a right agn have a good day

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Classify the sequences as arithmetic geometric, Fibonacci -5,0,10,15,25

vovikov84 [41]

It is arithmetic.

It starts at - 5,

the next item is 0 then 5 and next is 15 ...

============

It isn't geometric. You are not multiplying by 5

The second term must be and not- 5 * 5 = - 25

============

A Fibonacci series adds the previous two terms together to get the next term

Usually it starts at 0, but it doesn't need to.

0,1,1,2,3,5,8,13,21,34 ....

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. A special safe lets you choose from 9 symbols for a 3-symbol-long pass code. You may enter a symbol any number of times. How m

Lady_Fox [76]

The question is an illustration of combination and there are 729 potential pass codes available

<h3>How to determine the number of potential pass codes?</h3>

The given parameters are

Symbols available = 9

Length of pass code = 3

From the question, we understand that a symbol may be entered any number of times.

This means that each of the 9 available symbols can be used three times

So, the number of potential pass codes is

Passcodes = 9 * 9 * 9

Evaluate the product

Passcodes = 729

Hence, there are 729 potential pass codes available