3 years ago

Or does anyone know how to solve this one ?

1 answer:

3 0

The small & large triangle are similar the we can write the following proportion/ratio:

8/(8+x) = 12/(12+18) ==> 12(8+x) =8(12+18) ==> 96+12x=240

12x =240-96 ==> 12x = 144 and x=12

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Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

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$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
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Step-by-step explanation:

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x+3.6-3.6=-4.75-3.6

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