In which quadrants are the y-coordinates positive

Mathematics

2 answers:

Butoxors [25]3 years ago

5 0

It would be quadrant 1

andreyandreev [35.5K]3 years ago

4 0

The first and second quadrants only.

You might be interested in

Math Help!!! How many x-intercepts does the graph of the function have?

dalvyx [7]

It can have however many x intercepts it wants,

BUT, to be a function it must pass the vertical line test. 
this means you have to look at the graph and see if a vertical line drawn anywhere hits the graph more than once. 
if it hits it more than once, it is NOT a function.

An example is a polynomial function to the infinite degree. That is
f(x) = lim (n --> infinity) [ x^n]
but only 1 y intercept (vertical line test remember)

6 0

3 years ago

Read 2 more answers

lad made 36 muffins.she put the same number of mugfins on each of 4 plates.how many muffins did she put on each plate?

geniusboy [140]

She put nine muffins on each plate. 9 x 4 is 36.

8 0

3 years ago

Csc (2sin^-1(-12/13)) that is 2 times inverse sin of -12/13

german

Answer: $-\frac{169}{120}$

I'm assuming you mean this:

$cosec(2sin^{-1}(\frac{-12}{13}))$

Recall what the cosecant function represents. It is the reciprocal of a sine function, and is often written in this form:

$\frac{1}{sinx}$

So, using the sine relationship:

$cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2sin^{-1}(\frac{-12}{13}))}$

Let $u = sin^{-1}(\frac{-12}{13})$
$cosec(2sin^{-1}(\frac{-12}{13})) = \frac{1}{sin(2u)}$
$= \frac{1}{2sinu \cdot cosu}$
$= \frac{1}{2sin(sin^{-1}(\frac{-12}{13})) \cdot cos(sin^{-1}(\frac{-12}{13}))}$
$= \frac{1}{\frac{-24}{13} \cdot \sqrt{1 - (\frac{-12}{13})^{2}}}$
$= \frac{1}{\frac{-24}{13}} \cdot \frac{1}{\sqrt{1 - \frac{144}{169}}}$
$= -\frac{13}{24} \cdot \frac{1}{\sqrt{\frac{25}{169}}}$
$= -\frac{13}{24} \cdot \frac{1}{\frac{5}{13}}$
$= -\frac{13}{24} \cdot \frac{13}{5}$
$= -\frac{169}{120}$