Answer:
x=2 and y=3
Step-by-step explanation:
y-2=x-1
or,x-y=-1.......(1)
again,
2x+1=y+2
or,2x-y=1.......(2)
now,
solving equations (1)&(2),we get,
x=2 and y=3
Okay so these statements are not true except for these
AK + BK = AC
Since BK = KC, so
AK + KC = AC
D bisects AK is not necessarily true since it is not stated that D and K lie on the same line.
According to above statement the required Inequality will be :
hence, the value of t should be less than 8 hours.
so, they can rent the meeting room for 7 hours.
Answer : The correct option is 
Step-by-step explanation :
According to the BODMAS rule, when the expression contains brackets open ((), {}, []) we have to first simplify the bracket followed by of (powers and roots etc.) and then we have to solve the division, multiplication, addition and subtraction from left to right order (respectively).
The given expression is:
![[\frac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}]^{-1}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%7B%283a%5E5b%29%5E%7B-2%7D%7D%5D%5E%7B-1%7D)
![=[\frac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}]^{1}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B%283a%5E5b%29%5E%7B-2%7D%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D%5E%7B1%7D)
![=[\frac{1}{(3a^5b)^{2}}\times \frac{1}{(2a^{-3}b^4)^2}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B%283a%5E5b%29%5E%7B2%7D%7D%5Ctimes%20%5Cfrac%7B1%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{1}{4a^{-6}b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7B1%7D%7B4a%5E%7B-6%7Db%5E8%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{a^6}{4b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7Ba%5E6%7D%7B4b%5E8%7D%5D)

Thus, the given expression is equivalent to 
After 45....- 315. After 0 min 0. And finally, After 3 hrs, -2700