Answer:
Train A = 128
Train B = 68
Step-by-step explanation:
We can set up a system of equations for this problem
Let A = # of tons of Train A
Let B = # of tons of Train B
A + B = 196
A = B + 60
Now, we plug in A for the first equation, using substitution
(B+60) + B = 196
2B + 60 = 196
Subtract 60 from both sides
2B = 136
Divide both sides by 2
B = 68
Plug in 68 for B in the 2nd equation
A = 68 + 60
A = 128
Checking work: 128 + 68 = 196 :D hope this helped
IF
2=5 ;
3=9 ; 3*5 - 3*2
4=48 ; 4*9 + 4*3
5=220 ; 5*48 - 5*4
6=1,350 6*220 + 6*5
7= 9408 7*1350 - 7*6
THEN 8 = 8*9408 + 8*7 = 75320
Answer:
\sqrt(3)[cos((4\pi )/(45))+isin((4\pi )/(45))]
Step-by-step explanation:
The first one.
To find the experimental probability, you will add the outcomes that resulted in even number and make that a ratio to the total number of outcomes.
<u>(12 + 14 + 18)</u>
(13 + 12 + 12 +14 + 11 + 18)
44/80 = 0.55
0.55 = 55%
The answer is choice D.
Answer:
70
Step-by-step explanation:
